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An air-conditioning system is shown in the figure below in which air flows over tubes carrying Refrigerant 134a. Air enters with a volumetric flow rate of (AV)1 = 190 m/min at 32°C, 1 bar, and exits at 22°C, 0.95 bar. Refrigerant enters the tubes at 5 bar with a quality of 20% and exits at 5 bar, 20°C. Air P1 = 1 bar T = 32°C = 305 K (AV), 3 Refrigerant 134a R-134a P3 = 5 bar X3 = 0.20 4 R-134a P4 = 5 bar T = 20°C Air 2+P2 = 0.95 bar T2 = 22°C = 295 K Ignoring heat transfer at the outer surface of the air conditioner, and neglecting kinetic and potential energy effects, determine at steady state: (a) the mass flow rate of the refrigerant, in kg/min. (b) the rate of heat transfer, in kJ/min, to the air from the refrigerant.

An air-conditioning system is shown in the figure below in which air flows over tubes carrying Refrigerant 134a. Air enters with a volumetric flow rate of (AV)1 = 190 m/min at 32°C, 1 bar, and exits at 22°C, 0.95 bar. Refrigerant enters the tubes at 5 bar with a quality of 20% and exits at 5 bar, 20°C. Air P1 = 1 bar T = 32°C = 305 K (AV), 3 Refrigerant 134a R-134a P3 = 5 bar X3 = 0.20 4 R-134a P4 = 5 bar T = 20°C Air 2+P2 = 0.95 bar T2 = 22°C = 295 K Ignoring heat transfer at the outer surface of the air conditioner, and neglecting kinetic and potential energy effects, determine at steady state: (a) the mass flow rate of the refrigerant, in kg/min. (b) the rate of heat transfer, in kJ/min, to the air from the refrigerant.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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An air-conditioning system is shown in the figure below in which air flows over tubes carrying Refrigerant 134a. Air enters with a volumetric flow rate of (AV)1 = 190 m/min at 32°C, 1 bar, and exits at 22°C, 0.95 bar. Refrigerant enters the tubes at 5 bar with a quality of 20% and exits at 5 bar, 20°C. Air P1 = 1 bar T = 32°C = 305 K (AV), 3 Refrigerant 134a R-134a P3 = 5 bar X3 = 0.20 4 R-134a P4 = 5 bar T = 20°C Air 2+P2 = 0.95 bar T2 = 22°C = 295 K Ignoring heat transfer at the outer surface of the air conditioner, and neglecting kinetic and potential energy effects, determine at steady state: (a) the mass flow rate of the refrigerant, in kg/min. (b) the rate of heat transfer, in kJ/min, to the air from the refrigerant.
Transcribed Image Text:An air-conditioning system is shown in the figure below in which air flows over tubes carrying Refrigerant 134a. Air enters with a volumetric flow rate of (AV)1 = 190 m/min at 32°C, 1 bar, and exits at 22°C, 0.95 bar. Refrigerant enters the tubes at 5 bar with a quality of 20% and exits at 5 bar, 20°C. Air P1 = 1 bar T = 32°C = 305 K (AV), 3 Refrigerant 134a R-134a P3 = 5 bar X3 = 0.20 4 R-134a P4 = 5 bar T = 20°C Air 2+P2 = 0.95 bar T2 = 22°C = 295 K Ignoring heat transfer at the outer surface of the air conditioner, and neglecting kinetic and potential energy effects, determine at steady state: (a) the mass flow rate of the refrigerant, in kg/min. (b) the rate of heat transfer, in kJ/min, to the air from the refrigerant.
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