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The figure as shown below is a rigid bar which is supported by two rods and a pin support. If the said connections is stress- free, determine the increase or decrease of the temperature in degrees Celsius that will resulted with a tensile stress of EN mPa for the brass rod. Brass L= 2 m A = 1200 mm? E = 100 GPa C a = 18.7 x 10-6/°C 3 m 2 m Copper L= 3 m A = 1500 mm? E = 120 GPa a = 16.8 × 10-6/°C Note: Neglect the weight of the bar and assumes that the two rods will subjected to same temperature change

The figure as shown below is a rigid bar which is supported by two rods and a pin support. If the said connections is stress- free, determine the increase or decrease of the temperature in degrees Celsius that will resulted with a tensile stress of EN mPa for the brass rod. Brass L= 2 m A = 1200 mm? E = 100 GPa C a = 18.7 x 10-6/°C 3 m 2 m Copper L= 3 m A = 1500 mm? E = 120 GPa a = 16.8 × 10-6/°C Note: Neglect the weight of the bar and assumes that the two rods will subjected to same temperature change

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The figure as shown below is a rigid bar which is supported by two rods and a pin support. If the said connections is stress- free, determine the increase or decrease of the temperature in degrees Celsius that will resulted with a tensile stress of EN mPa for the brass rod. Brass L= 2 m A = 1200 mm? E = 100 GPa C a = 18.7 x 10-6/°C 3 m 2 m Copper L= 3 m A = 1500 mm? E = 120 GPa a = 16.8 × 10-6/°C Note: Neglect the weight of the bar and assumes that the two rods will subjected to same temperature change
Transcribed Image Text:The figure as shown below is a rigid bar which is supported by two rods and a pin support. If the said connections is stress- free, determine the increase or decrease of the temperature in degrees Celsius that will resulted with a tensile stress of EN mPa for the brass rod. Brass L= 2 m A = 1200 mm? E = 100 GPa C a = 18.7 x 10-6/°C 3 m 2 m Copper L= 3 m A = 1500 mm? E = 120 GPa a = 16.8 × 10-6/°C Note: Neglect the weight of the bar and assumes that the two rods will subjected to same temperature change
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