The Fate of Carbon Atoms in Amino Acids A transamination can be summarized as an amino group (-NH3+) of an amino acid and the keto group (C-O) of an a-keto acid changing places and forming different amino acid and a-keto acid products, as in the generic reaction below: amino acid 1 + a-keto acid 1 → a-keto acid 2 + amino acid 2 Draw the a-keto acid product of the transamination of an a-keto acid with an amino acid that has the side chain X (double click an existing atom and type X). O || RC-COO + View Available Hint(e) O || +H₂N-CH-C-0- I X 18 of 20 →? Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. Show formal charges on all atoms. Double click an existing atom and type X to enter the side chain.
Neutral Amino Acids
Amino acids which do not have any charge on them are neutral amino acids.
Globular Protein
The globular proteins refer to the shape of protein specifically spherical in nature apart from spherical form fibrous, disordered and membrane-bound proteins exist. These globular proteins are miscible in water and form a colloidal solution rather than other types which might not exhibit solubility. Many classes of the fold are found in globular proteins, which render them a sphere shape. Globular fold containing proteins usually are referred to by the term globin.
Dimer
Dimers are basic organic compounds, which are derivates of oligomers. It is formed by the combination of two monomers which could potentially be strong or weak and in most cases covalent or intermolecular in nature. Identical monomers are called homodimer, the non-identical dimers are called heterodimer. The method by which dimers are formed is known as “dimerization”.
Dipeptide
A dipeptide is considered a mixture of two distinct amino acids. Since the amino acids are distinct, based on their composition, two dipeptide's isomers can be produced. Various dipeptides are biologically essential and are therefore crucial to industry.
Step by step
Solved in 2 steps with 2 images