The failure stress of a homogeneous steel bar having a diameter of 10 mm is 250 MPa. Using a factor of safety of 2.0 and if the elastic mođulus andlength of the bar is 200 GPa and 2 m respectively, calculate the elongation in mm of the bar corresponding to the maximum load it can support.(А) 5(в) 2.51.25D) 0.625

Answered: Image /qna-images/answer/195da0aa-8edd-4b93-823c-52a6f70a4b02.jpg

The failure stress of a homogeneous steel bar having a diameter of 10 mm is 250 MPa. Using a factor of safety of 2.0 and if the elastic modulus and length of the bar is 200 GPa and 2 m respectively, calculate the elongation in mm of the bar corresponding to the maximum load it can support. (А) 5 (в) 2.5 (с) 1.25 D) 0.625

The failure stress of a homogeneous steel bar having a diameter of 10 mm is 250 MPa. Using a factor of safety of 2.0 and if the elastic modulus and length of the bar is 200 GPa and 2 m respectively, calculate the elongation in mm of the bar corresponding to the maximum load it can support. (А) 5 (в) 2.5 (с) 1.25 D) 0.625

Materials Science And Engineering Properties

1st Edition

ISBN:9781111988609

Author:Charles Gilmore

Publisher:Charles Gilmore

Chapter6: Introduction To Mechanical Properties

Section: Chapter Questions

Problem 6.3P: Compare the engineering and true secant elastic moduli for the natural rubber in Example Problem 6.2...

See similar textbooks

Similar questions

The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.
Vol. Strain.
A steel bar 30 mm in diameter and 2 m long is encased in a shell of cast iron 5 mm thick. Compute the stress in each material, in MPa, if a compressive axial load of 150 kN is applied to the assembly. For steel, E = 200 MPa and for cast iron, E = 100 %3D GPa ( Select the correct response(s): 29.96 MPa 76.39 MPa 212.21 MPa 106.10 MPa 136.32 MPa 152.79 MPa 59.92 MPa 272.84 MPa
PROBLEM 1) An aluminum bar carries the axial loads at the positions shown. If E=70GPA, compute the total deformation of the bar. Assume that the bar is suitably braced to prevent buckling. 0.4m D What is the axial stress o Ag in Pa? 10KN 0.8m 0.4m B 5KN 0.6m 20KN A=800 mm? A=1,200 mm²
A mild steel bar of square cross-section 40 mm x 40 mm is 400 mm long it is subjected to a longitudinal tensile stress of 440 N/mm² and lateral compressive stress is 200 N/mm² in perpendicular directions. E = 2 x 105 N/mm², μ = 0.3. What is the approximate elongation of the bar in the longitudinal direction?
A 3m long steel plate having a cross section of 25mm by 300mm is use as a hanger and subjectedto a tensile load of 1070 kN. The proportional limit of the steel is assumed to be 200 MPa. If thePoisson’s ratio is 0.25, determine the following;a. The transverse strain,b. The total axial deformation, andc. The transverse dimensional change along 300mm.
AN ALUMINUM TUBE IS FASTENED BETWEEN A STEEL ROD AND BRONZE ROD AS SHOWN IN THE FIGURE. AXIAL LOADS ARE APPLIED AT THE POSITIONS INDICATED. FIND THE VALUE OF P THAT WILL NOT EXCEED A MAXIMUM OVERALL DEFORMATION OF 5mm OR A STRESS IN THE STEEL OF 120MPa, IN BRONZE OF 130 MPa AND IN ALUMINUM OF 90 MPa. Modulus of Elasticty of Bronze = 80 GPa, Aluminum = 65 GPa and Steel = 210 GPa. 2P P 3P 4P L = 500mm 800 A = 400mm² 900 600 700 C
For a given steel cube section subjected to three dimensional state of principal stress. 75N/mm² ŠI 150 N/mm 30 N/mm² Consider yield stress = 250 N/mm², and µ = 0.3 The value of factor of safety according to maximum strain energy theory. -X
The composite shaft consists of a copper rod that fits loosely inside an aluminum sleeve. The two components are attached to a rigid wall at one end and joined with an end-plate at the other end. Determine the maximum shear stress in each material when the 2-kN m torque is applied to the end-plate. Use G = 26 GPa for aluminum and G =47 GPa for copper.
The shown plate is 60 mm thick and it is made of Magnesium Am1004-T61. The plate is fitted between the rigid frictionless supports as shown and at T, = 20°C it is stress free. Find the stresses in the x and y directions when the temperature increases to T, = 58°C. %3D 150 mm 150 mm Select one: O x: 0 MPa, y: 42.864 MPa Ox: 22.1 MPa, y: 44.2 MPa Ox: 0 MPa, y: 44.2 MPa Ox: 0 MPa, y: 17.8 MPa O x: 13.2 MPa, y: 44.2 MPa Ox: 0 MPa, y: 67.4 MPa 3:10 PM O G 4) ENG 1/31/2021
STRAIN
2. A rod is composed of an aluminum section rigidly attached between steel and bronze sections as shown in the figure. Axial loads are applied at the positions indicated. The cross-sectional area of the rod is 300sq.mm. Express your answer in MPa. Determine the stress in the steel. b. a. Determine the stress in the aluminum. Determine the stress in the bronze. C. STEEL ALUMINUM BRONZE 56kN 14kN -0.6m- -0.9m- -0.76m-