105Ar B/sO 0 814 7:26TNT8 quilgo.com/link/m5xnZhneGfUMB28O 01:23:211 RequiredTwo round bars are joined and used as atension member as illustrated. The modulusof elasticity is 200 GPa for steel and 70 GPafor aluminum.Aluminum100 mm diameterbar50 mm diaineterSteel bar-280mm-400 mmDetermine the magnitude of the force P (inkN) that will lengthen the two bars 0.25 mm.Your answerCLASS CODE *326732753282 At the proportional limit, the axial load of a0.80-in-diameter bar was 5600 lb. A 2.30-in.gauge length on the bar has increased by0.0044 inch.Determine the stress (in ksi) in the bar at theproportional limit. *6*Determine the strain in the bar.7Determine the elastic modulus (in ksi). *Ket

Answered: Image /qna-images/answer/565e5eea-b79f-415f-9824-a657bc9c0950.jpg

Answered: At the proportional limit, the axial…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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ProbleT = - An aluminum bar has diameter d = 40 mm, shear modulus of elasticity G = 27 GPa, and torque T = 300 N.m. (a) Determine the maximum shear, tensile, and compressive stresses in the bar, and show these stresses on sketches of properly oriented stress elements. (b) Determine the corresponding maximum strains (shear, tensile, and compressive) in the bar and show these strains on sketches of the deformed elements. |d=40 mm T= 300 N-m
1. The assembly has the diameters and material makeup indicated. If it fits securely between its fixed supports when the temperature is T; = 70°F, determine the average normal stress in each material when the temperature reaches T2 = 130°F. 304 Stainless steel - 2014-T6 Aluminum -C 86100 Bronze A 12 in. 8 in. D C 4 in. -4 ft- 6 ft- 3 ft
The assembly shown in figure below consists of a light rigid bar AB, pinned at O, that is attached to the steel and aluminum rods. In the position shown, bar AB is horizontal and there is a gap, A = 5 mm, between the lower end of the steel rod and its pin support at C. Compute the stress in the aluminum rod when the lower end of the steel rod is touch to its support. A 0.75 m Steel A = 250 mm E = 200 GPa *i* O 1.5 m Aluminum L = 2m A = 300 mm' E = 70 GPa B D
From the given illustration below, the force acting on B is equal to 25 kN, on C = 20 kN, and on D = 30 kN. If the cross sectional area of the material is 600 sg.mm, what is the maximum stress in the bar? FINAL EXAM 一- A B FINAL EXAM
Wire BC has a diameter of 0.10 in. And its material has the stress-strain characteristics shown in the figure. Determine the vertical displacement of the handle D if the pull on the handle is slowly increased and reaches the magnitude of P = 655 lb. o (ksi) 40 pulg 80 70 B 50 pulg - 30 pulg € (pulg/pulg) 0.007 0.12
Axial loads are applied with rigid bearing plates to the solid cylindrical rods shown in the figure. One load of P=34 kips is applied to the assembly at A, two loads of Q=25 kips are applied at B, and two loads of R=37 kips are applied at C. The normal stress magnitude in aluminum rod (1) must be limited to 16 ksi. The normal stress magnitude in steel rod (2) must be limited to 32 ksi. The normal stress magnitude in brass rod (3) must be limited to 24 ksi. Determine the minimum diameter (in in rounded to the nearest thousandths) required for rod 2.
Axial loads are applied with rigid bearing plates to the solid cylindrical rods shown in the figure. One load of P = 30 kips is applied to the assembly at A, two loads of Q = 20 kips are applied at B, and two loads of R = 35 kips are applied at C. The normal stress magnitude in aluminum rod (1) must be limited to 15 ksi. The normal stress magnitude in steel rod (2) must be limited to 33 ksi. The normal stress magnitude in brass rod (3) must be limited to 22 ksi. Determine the minimum diameter required for each of the three rods. (1) R В D di in. d2 = i in. dz = i in.
Question 3 A pair of lateral load is applied to a 3 m steel beam as in Figure Q3a to bend it plastically. The beam has a solid rectangular cross-section (30mm x 50mm) as in Figure Q3b. The steel behaves in elastic-perfectly plastic behavior with Yield Stress of 200 MPa. When 50% plastic condition at critical section, determine: a. the value of load P b. the Yielded Length, Lp corresponding to condition in part (a). 1.5P P 1m 1m Figure Q3a 1m 30mm 50mm Figure Q3b
At a point in a machine component that is subjected to plane stress, the normal and shear stresses are o, = 60 MPa, o, = 110 MPa, and Txy = 28 MPa, acting in the directions shown in the figure. At this point, determine the strain components &x, y, z, and Yxy. Assume that E = 73 GPa and v=0.29 for the machine component. £x = que 11 Ox Ez = με με με μrad
At a temperature of 28.42 °C a 0.4-mm gap exists between the ends of the rods shown. At a later time when the temperature has reached 137.38°C, determine the magnitude of the normal stress (in MPa) in the steel rod if L = 339.61 mm and M=240 mm. Round off the final answer to four decimal places. d ... В Aluminum Stainless steel A = 2000 mm² E = 75 GPa a = 23 × 10-6°C A = 800 mm² E = 190 GPa a = 17.3 × 10-6°C
Knowing that a 0.02in gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to -11ksi, (b) the corresponding exact length (2 decimal places in 103 inches) of the aluminum bar. 0.02 in. 14 in. Bronze A = 2.4 in² E = 15 × 106 psi a = 12 x 10-6/°F 18 in. Aluminum A = 2.8 in² E = 10.6 × 106 psi a = 12.9 x 10-6/°F
3. The material is subjected to biaxial loading producing uniform normal stress ox and o, as shown. The strains are e, = -0.00065 and e, = -0.00040. Use E = 207 GPa and v = 0.35. Determine the following: (a) oz. Indicate tension or compression. Use 2 decimal places. (b) ơy. Indicate tension or compression. Use 2 decimal places. (c) Change in the thickness of the material. Indicate elongation or contraction. Use 5 decimal places and scientific notation of x 10-3 (Example: . (25 pts) x 10-3) y Oy x. Oy t = 16 mm

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At the proportional limit, the axial load of a 0.80-in-diameter bar was 5600 lb. A 2.30-in. gauge length on the bar has increased by 0.0044 inch. Determine the stress (in ksi) in the bar at the proportional limit. * Determine the strain in the bar. * 7 Determine the elastic modulus (in ksi). Ket