The equilibrium for the precipitation of CaCO3 from its ions in solution is 2.2 x 10*8. Ca+2 (aq) + CO3 (ag) <--> CACO3(s). What is the equilibrium constant for the reverse of this equation, where CaCO3 dissolves in water to form ions? Oa. 2.2 x 10-8 Ob. 4.5 x 10+9 Oc. C. 2.2 x 10-8 Od. 4.5 x 10-9

The equilibrium for the precipitation of CaCO3 from its ions in solution is 2.2 x 10*8. Ca+2 (aq) + CO3 (ag) <--> CACO3(s). What is the equilibrium constant for the reverse of this equation, where CaCO3 dissolves in water to form ions? Oa. 2.2 x 10-8 Ob. 4.5 x 10+9 Oc. C. 2.2 x 10-8 Od. 4.5 x 10-9

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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