The equilibrium constant, Kp, for the following reaction is 55.6 at 698 K: H₂(9) + I₂(9) 2HI(g) Calculate the equilibrium partial pressures of all species when H₂ and I2, each at an intitial partial pressure of 2.07 atm, are Introduced into an evacuated vessel at 698 K. PH₂= P12= PHI= Submit Answer to access Important values if needed for this question. atm atm atm Retry Entire Group 9 more group attempts remaining Previous Next

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The equilibrium constant, \( K_p \), for the following reaction is 55.6 at 698 K:

\[ \text{H}_2(g) + \text{I}_2(g) \rightleftharpoons 2\text{HI}(g) \]

Calculate the equilibrium partial pressures of all species when \( \text{H}_2 \) and \( \text{I}_2 \), each at an initial partial pressure of 2.07 atm, are introduced into an evacuated vessel at 698 K.

- \( P_{\text{H}_2} = \_\_\_\_\_ \) atm
- \( P_{\text{I}_2} = \_\_\_\_\_ \) atm
- \( P_{\text{HI}} = \_\_\_\_\_ \) atm

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Transcribed Image Text:The equilibrium constant, \( K_p \), for the following reaction is 55.6 at 698 K: \[ \text{H}_2(g) + \text{I}_2(g) \rightleftharpoons 2\text{HI}(g) \] Calculate the equilibrium partial pressures of all species when \( \text{H}_2 \) and \( \text{I}_2 \), each at an initial partial pressure of 2.07 atm, are introduced into an evacuated vessel at 698 K. - \( P_{\text{H}_2} = \_\_\_\_\_ \) atm - \( P_{\text{I}_2} = \_\_\_\_\_ \) atm - \( P_{\text{HI}} = \_\_\_\_\_ \) atm There are buttons for submitting the answer and retrying the entire group, with 9 more group attempts remaining.
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