The initial concentrations or pressures of reactants and products are given for each of the following systems. Calculate the reaction quotient and determine the direction in which each system will proceed to reach equilibrium. Reaction Kc value Concentrations 2NH3 (9) N₂ (g) + 3H₂ (g) 17 [NH3] = 0.20 M, [N₂] = 1.00 M, [H₂] = 1.00 M 2NH3 (9) N₂ (g) + 3H₂ (g) 6.8 x 104 NH3 = 3.0 atm, N₂ = 2.0 atm, H₂ = 1.0 atm 2SO3 (g)2SO₂ (g) + O₂ (g) 0.230 [SO3] = 0.00 M, [SO₂] = 1.00 M, [O₂] = 1.00 M

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**Initial Concentrations and Direction to Equilibrium**

This table displays the initial concentrations or pressures of reactants and products for several chemical reactions, along with their respective equilibrium constant (\(K_c\)) values. To determine the movement of each system toward equilibrium, we calculate the reaction quotient \(Q\) and compare it to the equilibrium constant \(K_c\). 

| Reaction | \(K_c\) value | Concentrations |
|----------|---------------|----------------|
| \(2\text{NH}_3 (g) \leftrightarrow \text{N}_2 (g) + 3\text{H}_2 (g)\) | 17 | \([\text{NH}_3] = 0.20\text{ M}, [\text{N}_2] = 1.00\text{ M}, [\text{H}_2] = 1.00\text{ M}\) |
| \(2\text{NH}_3 (g) \leftrightarrow \text{N}_2 (g) + 3\text{H}_2 (g)\) | \(6.8 \times 10^4\) | \(\text{NH}_3 = 3.0\text{ atm}, \text{N}_2 = 2.0\text{ atm}, \text{H}_2 = 1.0\text{ atm}\) |
| \(2\text{SO}_3 (g) \leftrightarrow 2\text{SO}_2 (g) + \text{O}_2 (g)\) | 0.230 | \([\text{SO}_3] = 0.00\text{ M}, [\text{SO}_2] = 1.00\text{ M}, [\text{O}_2] = 1.00\text{ M}\) |

**Analysis:**

1. **For the first reaction \(2\text{NH}_3 (g) \leftrightarrow \text{N}_2 (g) + 3\text{H}_2 (g)\) with \(K_c = 17\):**
   - **Given concentrations:** \([\text{NH}_3] = 0.20\text{ M}, [\text{N}_2] = 1.00\text{ M}, [
Transcribed Image Text:**Initial Concentrations and Direction to Equilibrium** This table displays the initial concentrations or pressures of reactants and products for several chemical reactions, along with their respective equilibrium constant (\(K_c\)) values. To determine the movement of each system toward equilibrium, we calculate the reaction quotient \(Q\) and compare it to the equilibrium constant \(K_c\). | Reaction | \(K_c\) value | Concentrations | |----------|---------------|----------------| | \(2\text{NH}_3 (g) \leftrightarrow \text{N}_2 (g) + 3\text{H}_2 (g)\) | 17 | \([\text{NH}_3] = 0.20\text{ M}, [\text{N}_2] = 1.00\text{ M}, [\text{H}_2] = 1.00\text{ M}\) | | \(2\text{NH}_3 (g) \leftrightarrow \text{N}_2 (g) + 3\text{H}_2 (g)\) | \(6.8 \times 10^4\) | \(\text{NH}_3 = 3.0\text{ atm}, \text{N}_2 = 2.0\text{ atm}, \text{H}_2 = 1.0\text{ atm}\) | | \(2\text{SO}_3 (g) \leftrightarrow 2\text{SO}_2 (g) + \text{O}_2 (g)\) | 0.230 | \([\text{SO}_3] = 0.00\text{ M}, [\text{SO}_2] = 1.00\text{ M}, [\text{O}_2] = 1.00\text{ M}\) | **Analysis:** 1. **For the first reaction \(2\text{NH}_3 (g) \leftrightarrow \text{N}_2 (g) + 3\text{H}_2 (g)\) with \(K_c = 17\):** - **Given concentrations:** \([\text{NH}_3] = 0.20\text{ M}, [\text{N}_2] = 1.00\text{ M}, [
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