The equilibrium constant, Kp, for the following reaction is 0.160 at 298 K. 2NOBr(g)2NO(g) + Br₂(g) If an equilibrium mixture of the three gases in a 17.8 L container at 298 K contains NOBr at a pressure of 0.301 atm and NO at a pressure of 0.376 atm, the equilibrium partial pressure of Br₂ is atm. Submit Answer Retry Entire Group 9 more group attempts remaining
The equilibrium constant, Kp, for the following reaction is 0.160 at 298 K. 2NOBr(g)2NO(g) + Br₂(g) If an equilibrium mixture of the three gases in a 17.8 L container at 298 K contains NOBr at a pressure of 0.301 atm and NO at a pressure of 0.376 atm, the equilibrium partial pressure of Br₂ is atm. Submit Answer Retry Entire Group 9 more group attempts remaining
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The equilibrium constant, Kp, for the following reaction is 0.160 at 298 K.
2NOBr(g)2NO(g) + Br₂ (9)
If an equilibrium mixture of the three gases in a 17.8 L container at 298 K contains NOBr at a pressure of 0.301 atm
and NO at a pressure of 0.376 atm, the equilibrium partial pressure of Br₂ is
atm.
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C
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Transcribed Image Text:eq
req
req
1req
2req
s 2req
#
3
20
The equilibrium constant, Kp, for the following reaction is 0.160 at 298 K.
2NOBr(g)2NO(g) + Br₂ (9)
If an equilibrium mixture of the three gases in a 17.8 L container at 298 K contains NOBr at a pressure of 0.301 atm
and NO at a pressure of 0.376 atm, the equilibrium partial pressure of Br₂ is
atm.
E
D
F3
C
Submit Answer
$
4
000
888
R
F
V
Show Hint
%
5
Retry Entire Group 9 more group attempts remaining
[References]
Use the References to access important values if needed for this question.
T
Cengage Learning Cengage Technical Support
FS
G
<<
6
B
MacBook Air
F6
Y
H
Topics]
&
7
N
U
J
*
00-
8
▶11
FB
1
M
(
9
K
O
V
of
)
O
L
F10
P
A.
command
:
F11
;
Previous
+
=
[
git
Next>
Save and Exit
B
option
F12
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