The equilibrium constant, Kp, for the following reaction is 0.160 at 298 K. 2NOBr(g)2NO(g) + Br₂(g) If an equilibrium mixture of the three gases in a 17.8 L container at 298 K contains NOBr at a pressure of 0.301 atm and NO at a pressure of 0.376 atm, the equilibrium partial pressure of Br₂ is atm. Submit Answer Retry Entire Group 9 more group attempts remaining

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The equilibrium constant, Kp, for the following reaction is 0.160 at 298 K.
2NOBr(g)2NO(g) + Br₂ (9)
If an equilibrium mixture of the three gases in a 17.8 L container at 298 K contains NOBr at a pressure of 0.301 atm
and NO at a pressure of 0.376 atm, the equilibrium partial pressure of Br₂ is
atm.
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Transcribed Image Text:eq req req 1req 2req s 2req # 3 20 The equilibrium constant, Kp, for the following reaction is 0.160 at 298 K. 2NOBr(g)2NO(g) + Br₂ (9) If an equilibrium mixture of the three gases in a 17.8 L container at 298 K contains NOBr at a pressure of 0.301 atm and NO at a pressure of 0.376 atm, the equilibrium partial pressure of Br₂ is atm. E D F3 C Submit Answer $ 4 000 888 R F V Show Hint % 5 Retry Entire Group 9 more group attempts remaining [References] Use the References to access important values if needed for this question. T Cengage Learning Cengage Technical Support FS G << 6 B MacBook Air F6 Y H Topics] & 7 N U J * 00- 8 ▶11 FB 1 M ( 9 K O V of ) O L F10 P A. command : F11 ; Previous + = [ git Next> Save and Exit B option F12
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