The reaction 2C0(g) + MoO2(s)=CO2(g) +Mo(s) is reaching equilibrium. How would increase the volume of the container affects the reaction? A) The equilibrium of this reaction will move forward (to the right). B) The equilibrium of this reaction will move backward (to the left). C) The equilibrium of this reaction will not change. D) The equilibrium of this reaction can not be decided.

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Chapter1: Chemical Foundations
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The reaction 2C0(g) + MoO2(s) = CO2(g) +Mo(s) is reaching
equilibrium. How would increase the volume of the container
affects the reaction?
A) The equilibrium of this
reaction wilImove
forward (to the right).
B) The equilibrium of this
reaction will move
backward (to the left).
C) The equilibrium of this
reaction will not change.
D) The equilibrium of this
reaction can not be
decided.
11165
A
W
Air
F10
F11
F12
F8
F9
8
{
P.
+ I|
Transcribed Image Text:A аpp.101еdu.co Update Question 7 of 11 Submit The reaction 2C0(g) + MoO2(s) = CO2(g) +Mo(s) is reaching equilibrium. How would increase the volume of the container affects the reaction? A) The equilibrium of this reaction wilImove forward (to the right). B) The equilibrium of this reaction will move backward (to the left). C) The equilibrium of this reaction will not change. D) The equilibrium of this reaction can not be decided. 11165 A W Air F10 F11 F12 F8 F9 8 { P. + I|
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