3. Consider the reaction for the decomposition of hydrogen disulfide. 2 H₂S (g) + 2 H₂(g) + S₂ (g) K₂ = 1.67 x 10-7 If the initial concentration of H₂S is 0.0250 M, what are the equilibrium concentration of H₂ and S₂?

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3. Consider the reaction for the decomposition of hydrogen disulfide.
2 H₂S (g) + 2 H₂(g) + S₂ (g) Ke=1.67 x 10-7
If the initial concentration of H₂S is 0.0250 M, what are the equilibrium concentration of H₂
and S₂?
Answer:
Initial
Change
Equilibrium
CH 122 General Chemistry
2 H₂S (g)
0.0250
0.0250-x
K =
[H₂][S₂]
[H₂S]
1.67 x 10-7-
2 H₂(g) +
0
+X
X
(x)(x)
0.0250-x 0.0250
S₂ (g)
0
Equilibrium Solved Problems
x = 6.32 x 10-5
The equilibrium concentrations of H₂ and S2 are 6.32 x 10-5 M
+X
X
Transcribed Image Text:3. Consider the reaction for the decomposition of hydrogen disulfide. 2 H₂S (g) + 2 H₂(g) + S₂ (g) Ke=1.67 x 10-7 If the initial concentration of H₂S is 0.0250 M, what are the equilibrium concentration of H₂ and S₂? Answer: Initial Change Equilibrium CH 122 General Chemistry 2 H₂S (g) 0.0250 0.0250-x K = [H₂][S₂] [H₂S] 1.67 x 10-7- 2 H₂(g) + 0 +X X (x)(x) 0.0250-x 0.0250 S₂ (g) 0 Equilibrium Solved Problems x = 6.32 x 10-5 The equilibrium concentrations of H₂ and S2 are 6.32 x 10-5 M +X X
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