At a certain temperature, the equilibrium constant K for the following reaction is 7.8 × 108 NO₂(g) + NO(g) 2 NO₂(g) Use this information to complete the following table. Suppose a 11. L reaction vessel is filled with 1.4 mol of NO₂. What can you say about the composition of the mixture in the vessel at equilibrium? What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. 2 NO₂(9) L NO3(9) + NO (9) What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. 2NO3(9)+2NO(9) 4 NO₂(9) L There will be very little NO3 and NO. O There will be very little NO₂. O Neither of the above is true. K = 0 K = 0

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**Kinetics and Equilibrium: Using the General Properties of Equilibrium Constants**

---

At a certain temperature, the equilibrium constant \( K \) for the following reaction is \( 7.8 \times 10^{-8} \):

\[ 
\text{NO}_3(g) + \text{NO}(g) \rightarrow 2\text{NO}_2(g) 
\]

Use this information to complete the following table.

---

**Suppose a 1 L reaction vessel is filled with 1.4 mol of NO\(_2\). What can you say about the composition of the mixture in the vessel at equilibrium?**

- [ ] There will be very little NO\(_3\) and NO.
- [ ] There will be very little NO\(_2\).
- [ ] Neither of the above is true.

---

**What is the equilibrium constant for the following reaction?**
Round your answer to 2 significant digits.

\[ 
2\text{NO}_2(g) \rightarrow \text{NO}_3(g) + \text{NO}(g)
\]

\[ 
K = \text{[ \_\_ ]}
\]

---

**What is the equilibrium constant for the following reaction?**
Round your answer to 2 significant digits.

\[ 
2\text{NO}_3(g) + 2\text{NO}(g) \rightarrow 4\text{NO}_2(g)
\]

\[ 
K = \text{[ \_\_ ]}
\]

---

*Note*: Use the principles of chemical equilibrium and the provided equilibrium constant to determine the answers.

Buttons: [Explanation] [Check]

© 2022 McGraw Hill LLC. All Rights Reserved.
Transcribed Image Text:**Kinetics and Equilibrium: Using the General Properties of Equilibrium Constants** --- At a certain temperature, the equilibrium constant \( K \) for the following reaction is \( 7.8 \times 10^{-8} \): \[ \text{NO}_3(g) + \text{NO}(g) \rightarrow 2\text{NO}_2(g) \] Use this information to complete the following table. --- **Suppose a 1 L reaction vessel is filled with 1.4 mol of NO\(_2\). What can you say about the composition of the mixture in the vessel at equilibrium?** - [ ] There will be very little NO\(_3\) and NO. - [ ] There will be very little NO\(_2\). - [ ] Neither of the above is true. --- **What is the equilibrium constant for the following reaction?** Round your answer to 2 significant digits. \[ 2\text{NO}_2(g) \rightarrow \text{NO}_3(g) + \text{NO}(g) \] \[ K = \text{[ \_\_ ]} \] --- **What is the equilibrium constant for the following reaction?** Round your answer to 2 significant digits. \[ 2\text{NO}_3(g) + 2\text{NO}(g) \rightarrow 4\text{NO}_2(g) \] \[ K = \text{[ \_\_ ]} \] --- *Note*: Use the principles of chemical equilibrium and the provided equilibrium constant to determine the answers. Buttons: [Explanation] [Check] © 2022 McGraw Hill LLC. All Rights Reserved.
Expert Solution
Step 1

Given reaction: NO3(g) + NO(g) ⇌ 2NO2(g)

K = 7.8×10-8

We have to calculate the equilibrium constants for the reactions:

2NO2(g) ⇌ NO3(g) + NO(g)

2NO3(g) + 2NO(g) ⇌ 4NO2(g)

 

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