The equilibrium constant, Kc, for the following reaction is 57.6 at 277 K. 2CH₂Cl2 (9) CH4 (9) + CCl4 (9) When a sufficiently large sample of CH₂Cl₂ (g) is introduced into an evacuated vessel at 277 K, the equilibrium concentration of CC14 (g) is found to be 0.383 M. Calculate the concentration of CH₂Cl2 in the equilibrium mixture. [CH₂ Cl₂] = M

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The equilibrium constant, \( K_c \), for the following reaction is 57.6 at 277 K.

\[ 2 \text{CH}_2\text{Cl}_2 (g) \rightleftharpoons \text{CH}_4 (g) + \text{CCl}_4 (g) \]

When a sufficiently large sample of \(\text{CH}_2\text{Cl}_2 (g)\) is introduced into an evacuated vessel at 277 K, the equilibrium concentration of \(\text{CCl}_4 (g)\) is found to be 0.383 M.

Calculate the concentration of \(\text{CH}_2\text{Cl}_2\) in the equilibrium mixture.

\[
[\text{CH}_2\text{Cl}_2] = \boxed{\,\,} \,\, \text{M}
\]
Transcribed Image Text:The equilibrium constant, \( K_c \), for the following reaction is 57.6 at 277 K. \[ 2 \text{CH}_2\text{Cl}_2 (g) \rightleftharpoons \text{CH}_4 (g) + \text{CCl}_4 (g) \] When a sufficiently large sample of \(\text{CH}_2\text{Cl}_2 (g)\) is introduced into an evacuated vessel at 277 K, the equilibrium concentration of \(\text{CCl}_4 (g)\) is found to be 0.383 M. Calculate the concentration of \(\text{CH}_2\text{Cl}_2\) in the equilibrium mixture. \[ [\text{CH}_2\text{Cl}_2] = \boxed{\,\,} \,\, \text{M} \]
**Equilibrium Constant Calculation**

The equilibrium constant, \( K_c \), for the following reaction is \(1.80 \times 10^{-4}\) at 298 K.

\[ \text{NH}_4\text{HS} (s) \rightleftharpoons \text{NH}_3 (g) + \text{H}_2\text{S} (g) \]

**Problem Statement:**

Calculate the equilibrium concentration of \(\text{H}_2\text{S}\) when 0.525 moles of \(\text{NH}_4\text{HS} (s)\) are introduced into a 1.00 L vessel at 298 K.

\[[\text{H}_2\text{S}] = \_\_\_\_\_ \, \text{M} \]
Transcribed Image Text:**Equilibrium Constant Calculation** The equilibrium constant, \( K_c \), for the following reaction is \(1.80 \times 10^{-4}\) at 298 K. \[ \text{NH}_4\text{HS} (s) \rightleftharpoons \text{NH}_3 (g) + \text{H}_2\text{S} (g) \] **Problem Statement:** Calculate the equilibrium concentration of \(\text{H}_2\text{S}\) when 0.525 moles of \(\text{NH}_4\text{HS} (s)\) are introduced into a 1.00 L vessel at 298 K. \[[\text{H}_2\text{S}] = \_\_\_\_\_ \, \text{M} \]
Expert Solution
Step 1: Defining equilibrium constant!

Answer:

For any reaction, value of equilibrium constant KC is equal to the ratio of molar concentration of products and reactants at equilibrium.

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