The equilibrium constant, Ke, for the following reaction is 9.52x102 at 350 K. CH4 (g) + CC14 (g) =2 CH,Cl2 (g) Calculate the equilibrium concentrations of reactants and product when 0.245 moles of CH, and 0.245 moles of CC, are introduced into a 1.00 L vessel at 350 K. [ CH4 ] [ CC14 ] [ CH,Cl, ] = M M M

Introduction to Chemical Engineering Thermodynamics
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Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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Chapter1: Introduction
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The equilibrium constant, Ke, for the following reaction is 9.52x102 at 350 K.
CH4 (g) + CC14 (g) =2 CH,Cl2 (g)
Calculate the equilibrium concentrations of reactants and product when 0.245 moles of CH, and 0.245 moles of CC, are
introduced into a 1.00 L vessel at 350 K.
[ CH4 ]
[ CC14 ]
[ CH,Cl, ] =
M
M
M
Transcribed Image Text:The equilibrium constant, Ke, for the following reaction is 9.52x102 at 350 K. CH4 (g) + CC14 (g) =2 CH,Cl2 (g) Calculate the equilibrium concentrations of reactants and product when 0.245 moles of CH, and 0.245 moles of CC, are introduced into a 1.00 L vessel at 350 K. [ CH4 ] [ CC14 ] [ CH,Cl, ] = M M M
The equilibrium constant, K., for the following reaction is 10.5 at 350 K.
2CH,Cl,(g)CHĄ(g) + CC14(g)
Calculate the equilibrium concentrations of reactant and products when 0.283 moles of CH,Cl, are introduced into a 1.00
L vessel at 350 K.
[CH,Cl,] =
M
[CH4]
M
[CCL]
M
Transcribed Image Text:The equilibrium constant, K., for the following reaction is 10.5 at 350 K. 2CH,Cl,(g)CHĄ(g) + CC14(g) Calculate the equilibrium concentrations of reactant and products when 0.283 moles of CH,Cl, are introduced into a 1.00 L vessel at 350 K. [CH,Cl,] = M [CH4] M [CCL] M
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