The equilibrium constant (kc) for the following reaction is 6.7 × 10^-10 at 630°C. N2(s) + O2(g) = 2NO (g) What is the equilibrium constant for the reaction below at the same temperature? NO(g) = 1/2 N2(g) + 1/2 O2(g)

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The equilibrium constant (kc) for the following reaction is 6.7 × 10^-10 at 630°C. N2(s) + O2(g) = 2NO (g) What is the equilibrium constant for the reaction below at the same temperature? NO(g) = 1/2 N2(g) + 1/2 O2(g)
b. 0,79
c.
1.5
d.
3,9
e.
14
7. Nitrosyl bromide decomposes according to the chemical equation below.
2 NOBR(g) = 2 NO(g) + Br2(g)
When 0.260 atm of NOBR is sealed in a flask and allowed to reach equilibrium, 22% of thec NODI
decomposes. What is the equilibrium constant, Kp, for the reaction?
2.3 x 103
b.
a.
4.5 x 10-3
3.5 x 10-2
d. 4.8 x 10-2
с.
e.
8.0 x 102
8. The equilibrium constant, Ke, for the following reaction is 1.0 x 10 at 1500 K.
N2(g) + O2(g) = 2 NO(g)
If 0.570 M N2 and 0.570MO2 are allowed to equilibrate at 1500 K. what is the concentration of Ne
5.7 x 106 M
9.0 x 104 M
a.
b.
2.4 x 104 M
1.8 x 10-3 M
2.4 x 10-3 M
с.
d.
e.
9. The equilibrium constant (K.) for the following reaction is 6.7 x 10 10 at 630 °C.
N2(s) + O2(g) =2 NO(g)
What is the equilibrium constant for the reaction below at the same temperature?
NO(g) = 1/2 N2(g) + 1/2 O2(g)
3.9 x 104
a.
b. 5.5 x 104
7.5 x 108
с.
d. 1.5 x 10°
e. 3.0 x 10°
Transcribed Image Text:b. 0,79 c. 1.5 d. 3,9 e. 14 7. Nitrosyl bromide decomposes according to the chemical equation below. 2 NOBR(g) = 2 NO(g) + Br2(g) When 0.260 atm of NOBR is sealed in a flask and allowed to reach equilibrium, 22% of thec NODI decomposes. What is the equilibrium constant, Kp, for the reaction? 2.3 x 103 b. a. 4.5 x 10-3 3.5 x 10-2 d. 4.8 x 10-2 с. e. 8.0 x 102 8. The equilibrium constant, Ke, for the following reaction is 1.0 x 10 at 1500 K. N2(g) + O2(g) = 2 NO(g) If 0.570 M N2 and 0.570MO2 are allowed to equilibrate at 1500 K. what is the concentration of Ne 5.7 x 106 M 9.0 x 104 M a. b. 2.4 x 104 M 1.8 x 10-3 M 2.4 x 10-3 M с. d. e. 9. The equilibrium constant (K.) for the following reaction is 6.7 x 10 10 at 630 °C. N2(s) + O2(g) =2 NO(g) What is the equilibrium constant for the reaction below at the same temperature? NO(g) = 1/2 N2(g) + 1/2 O2(g) 3.9 x 104 a. b. 5.5 x 104 7.5 x 108 с. d. 1.5 x 10° e. 3.0 x 10°
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