The equilibrium constant, K, for the following reaction is 1.20x102 at 500 K. PCI,(9) PCly(9) + Cl2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.262 M PCI,, 5.61x102 M PCI, and 5.61x102 M Clz2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 4.78x102 mol of Cl2(9) is added to the flask? (PCIs) - M. (PCI,)- M. (Cl2) M.

Chemistry for Engineering Students
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Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.34PAE: 1’he reaction in Exercise 12.33 was repeated. This time, the reaction began when only NO was...
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Use the References to access important values if needed for this question.
The equilibrium constant, K, for the following reaction is 1.20x102 at 500 K.
PCI5(g) PCI3(9) + Clz(g)
An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.262 M PCIs, 5.61x102 M PCI, and
5.61x102 M CI,. What will be the concentrations of the three gases once equilibrium has been reestablished, if
4.78x102 mol of Cl2(g) is added to the flask?
[PCIg) -
M.
[PCI3)=
M.
(Cl2)
M.
%3D
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Transcribed Image Text:[Review Toples) References] Use the References to access important values if needed for this question. The equilibrium constant, K, for the following reaction is 1.20x102 at 500 K. PCI5(g) PCI3(9) + Clz(g) An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.262 M PCIs, 5.61x102 M PCI, and 5.61x102 M CI,. What will be the concentrations of the three gases once equilibrium has been reestablished, if 4.78x102 mol of Cl2(g) is added to the flask? [PCIg) - M. [PCI3)= M. (Cl2) M. %3D Submit Answer Retry Entire Group No more group attempts remain (Previous
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