The equilibrium constant for the following reaction is 1.80×10-2 at 698K. 2HI(g)H2(g) +I2(g) If an equilibrium mixture of the three gases at 698K contains 2.23×10-2 M HI(g) and 2.22×10-2 M H2, what is the equilibrium concentration of I2?   M

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Q: The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) H2(g) + I2(g)…

A: The reaction is  2HI(g) ---> H2(g) + I2(g) The equilibrium constant, K = 1.80×10-2 at 698 K.…