Please solve the question properly with steps.I can't seem to figure it out. The equation of angular displacement of a particle, moving in a circular path (radius200m) is given by e = 18t + 3t² – 2t³ where e is the angular displacement at the end oft sec. Find a) angular velocity and acceleration at start, b) time when the particlereaches its maximum angular velocity, and c) maximum angular velocity of theparticle.2.

Given: R = 200 m θ=18t+3t2-2t3 In θ direction only, the displacement of the particle is varying.

The equation of angular displacement of a particle, moving in a circular path (radius 200m) is given by e = 18t + 3t² – 2t³ where ☺ is the angular displacement at the end of t sec. Find a) angular velocity and acceleration at start, b) time when the particle reaches its maximum angular velocity, and c) maximum angular velocity of the particle.

The equation of angular displacement of a particle, moving in a circular path (radius 200m) is given by e = 18t + 3t² – 2t³ where ☺ is the angular displacement at the end of t sec. Find a) angular velocity and acceleration at start, b) time when the particle reaches its maximum angular velocity, and c) maximum angular velocity of the particle.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Please solve the question properly with steps.

I can't seem to figure it out.

The equation of angular displacement of a particle, moving in a circular path (radius
200m) is given by e = 18t + 3t² – 2t³ where e is the angular displacement at the end of
t sec. Find a) angular velocity and acceleration at start, b) time when the particle
reaches its maximum angular velocity, and c) maximum angular velocity of the
particle.
2.

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