) In an unused area of the test facility, lie two internal combustion engines that were brought in for assessment several years ago. Using what little information has been found, determine the relative efficiency of each. Take y for air as 1.4 for both.
) In an unused area of the test facility, lie two internal combustion engines that were brought in for assessment several years ago. Using what little information has been found, determine the relative efficiency of each. Take y for air as 1.4 for both.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Hello, so i have attached two images. the first image is the quetions, i need part b) answered if possible. i have attached my findings to part a) to add to the little information we know to help with part b if needed. Thnks

Transcribed Image Text:a) The company has two diesel-powered standby generators, both of
which are capable of supplying sufficient electrical power in the
event of a failure. Both diesel engines have the same details on
their name plates (given below), but one operates on the four-
stroke cycle, whilst the other operates on a two-stroke cycle. As
all the other information has been lost, you have been asked to
determine the brake power, indicated power, and thus confirm the
mechanical efficiency of each engine. Explain why these efficiency
values may be different for each engine.
Mean effective
550 KN/m²
pressure
Swept volume of
14 litres
cylinder
Speed of engine
150 revs/min
Brake torque
2000 Nm
Number of cylinders | 8
b) In an unused area of the test facility, lie two internal combustion
engines that were brought in for assessment several years ago.
Using what little information has been found, determine the
relative efficiency of each. Take y for air as 1.4 for both.

Transcribed Image Text:1. Brake Power
2. Indicated
Power
3. Mechanical
Efficiency
2-stroke engine
(10π) KW
154 kW
20.4%
4-stroke engine
(10) KW
77 kW
40.8%
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The p-v diagram all make sense, but the equations are unreadable. i dont understand where some units have come from etc, could you please further explain the equations. thnks, feel free to take the relevant amount of credits
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