Answered: The equation of a transverse wave… | bartleby

Related questions

Question

The equation of a transverse wave traveling
on a string is given by y = A sin(kx - wt).
Data: A=11 mm, k=35 rad/m, w= 500 rad/s.
1) What is the amplitude?
2) What is the frequency?
3) What is the wave velocity?
4) What is the wavelength?
5) For the same wave, find the maximum
transverse speed of a particle in the string.

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

What is the phase constant, maximum speed of particle & sign of wave direction?
The Function of a travelling wave on a string with a linear mass density of u = 3.0 kg/m is given by the following wave function: y(x,t) a) What is the wave speed? 0.25 sin(57TX + 16n), Here x and y are in meters and time is in seconds. b) In which direction is the wave travelling? c) How much tension is in the string? d) Find the particle velocity at position x= 1.5 m and at time t = 14 seconds e) Draw a snapshot of the wave for one whole wavelength at t = 14 seconds.
The equation for the displacement of a stationary wave on a string is given by y = 2 (sin 5πt)(cos 6πx), where x and y are in meters, and t is in seconds. Determine: b. the amplitude of the point P which lies at a distance of 75 cm from the end of the reflection!
A 1m long string is pinned at both ends. The string is plucked, and a standing wave is created. The wave number is ? = 4? rad/m.a) Calculate the wavelength of the wave.b) If there are 5 nodes in the string, find their positions.Answers: • 0.5 m• Xn = {0, 0.25, 0.5, 0.75, 1}
A sinusoidal wave is given by: y= 8 sin (2x - 5t) cm determine the transverse velocity vy of a point on this wave in cm/s at point x =8 cm for t=3 s.
Pls help on this question. Pls explain with steps.
Two waves are traveling on the same string. The displacement of the first is given by y₁ = 0.0300 sin(400лt - 2лx) and of the second by y2 = 0.0300 sin (400лt - 2x + 44), with x and y in meters and t in seconds. What is the amplitude of the resultant wave? i m
Consider a 1 meter-long string with a mass of 50 g attached to a string vibrator. The tension in the string is 80 N. When the string vibrator is turned on, it oscillates with a frequency of 64 Hz and produces a sinusoidal wave on the string with an amplitude of 4 cm and a constant wave speed. Give your answers to 3 sig fig. A)VWhat is the linear density of the medium?____kg/m B)What is the wave speed?____m/s C)What is the angular frequency?______Hz D) What is the time-averaged power supplied to the wave by the string vibrator?___W
A wave on a string is described by y ( x , t ) = (1.5 cm) sin ⁡ [2π( x/0.3 m + t/0.4 s ) + 0.1 ]. This equation will be used for the next three questions. a) Find the frequency (f) and wavelength using the equation, and then solve for the wave speed. Enter your answer in units of m/s below. b) At t = 0.2s, what is the displacement of the string at x = 0.5m? Answer in cm. c) Now assume the string is fixed on both ends. How long must the string be in order to produce a second-mode standing wave? Answer in m.
A steel wire is 5.00 m long and is stretched with a tension of 1400 N . The speed of propagation of a transverse wave on the wire is 800 m/s. a)What is the mass per unit length of the wire, μ? b)What is the mass of the wire?
What is the expression for the transverse velocity of the wave in a string given by y = A sin(kx-at)? v=aAcos(kx - cut) v = - @Acos(kx - cut) Ov= Acos(kx - out) Ov=kAcos(kx - cut) Ov=-kA cos(kx - out)