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What is the work function, W , of the metal surface? If this photocathode is illuminated by light with a wavelength 1 = 457.0 nm , what stopping а. b. voltage (absolute value), VHop , is needed to stop all of the photoelectrons from reaching the collector? What is the critical wavelength 1,? Light with any wavelength longer than 1 cannot С. produce any photoelectrons.

What is the work function, W , of the metal surface? If this photocathode is illuminated by light with a wavelength 1 = 457.0 nm , what stopping а. b. voltage (absolute value), VHop , is needed to stop all of the photoelectrons from reaching the collector? What is the critical wavelength 1,? Light with any wavelength longer than 1 cannot С. produce any photoelectrons.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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When a metal surface, in a photoelectric effect apparatus, is illuminated with light at 2 = 289.5 nm , the maximum kinetic energy of the photoelectrons produced is K 9. 31.95 еV . max What is the work function, W , of the metal surface? If this photocathode is illuminated by light with a wavelength 2 = 457.0 nm , what stopping а. b. voltage (absolute value), Vto is needed to stop all of the photoelectrons from reaching the stop collector? What is the critical wavelength 1,? Light with any wavelength longer than 1 cannot С. produce any photoelectrons.
Transcribed Image Text:When a metal surface, in a photoelectric effect apparatus, is illuminated with light at 2 = 289.5 nm , the maximum kinetic energy of the photoelectrons produced is K 9. 31.95 еV . max What is the work function, W , of the metal surface? If this photocathode is illuminated by light with a wavelength 2 = 457.0 nm , what stopping а. b. voltage (absolute value), Vto is needed to stop all of the photoelectrons from reaching the stop collector? What is the critical wavelength 1,? Light with any wavelength longer than 1 cannot С. produce any photoelectrons.
Waves in general: FORMULA PAGE 1 a y 1-dimensional wave equation: 1 a'y ; here v is the speed of the wave v? ôt? Solution: f(x- vt) or f(x+vt) Harmonic or sinusoidal waves: y(x,t)= Asin(kx- ot) 2л k 2n = 27f; v=- T v = f2 General Constants: -34 h = 6.626×10*J.s = 4.13567×10¬eV ·s ; (with recent revisions to the SI system of units Planck's Constant is defined to have an exact value: h= 6.62607015×10¯“J·s) –34 -19 hc = 1240 eV · nm; hc=1239.84eV · nm (for more accuracy); leV =1.6022×10-J = 299,792, 458 m /s (exact); -31 electron mass: m, =9.1094×10' kg proton mass: m, =1.6726×10-27 kg Photons: E = hf hc ; Protons: m,c² = 938.3MEV , Electrons: m.c² = 511.0keV %3| h = 1.0546x10 34J•s = 6.5821×10-1eV ·s Chapter 36. Diffraction Single slit diffraction: Minima: a sin 0, = ma, m=1,2,3,...where a is the slit width, note: there is a maximum at 0 = 0 sin(a) па Intensity: I(0) = ,, a = -sin(0) m a Circular aperture: First minimum: sin 0 = 1.22- Rayleigh's criterion ( 1 <d ): a =1.22- d Double slit experiment with slit separation d and slit width a: sin a Intensity: I(0) = I„(cos? B)| where B = -sin 0 , a = па -sin O Grating equation (normal incidence): d sin 0 = m order in which the grating is being used, d is the line or groove spacing m = 0,1, 2,3,... (maxima), where m is the
Transcribed Image Text:Waves in general: FORMULA PAGE 1 a y 1-dimensional wave equation: 1 a'y ; here v is the speed of the wave v? ôt? Solution: f(x- vt) or f(x+vt) Harmonic or sinusoidal waves: y(x,t)= Asin(kx- ot) 2л k 2n = 27f; v=- T v = f2 General Constants: -34 h = 6.626×10*J.s = 4.13567×10¬eV ·s ; (with recent revisions to the SI system of units Planck's Constant is defined to have an exact value: h= 6.62607015×10¯“J·s) –34 -19 hc = 1240 eV · nm; hc=1239.84eV · nm (for more accuracy); leV =1.6022×10-J = 299,792, 458 m /s (exact); -31 electron mass: m, =9.1094×10' kg proton mass: m, =1.6726×10-27 kg Photons: E = hf hc ; Protons: m,c² = 938.3MEV , Electrons: m.c² = 511.0keV %3| h = 1.0546x10 34J•s = 6.5821×10-1eV ·s Chapter 36. Diffraction Single slit diffraction: Minima: a sin 0, = ma, m=1,2,3,...where a is the slit width, note: there is a maximum at 0 = 0 sin(a) па Intensity: I(0) = ,, a = -sin(0) m a Circular aperture: First minimum: sin 0 = 1.22- Rayleigh's criterion ( 1 <d ): a =1.22- d Double slit experiment with slit separation d and slit width a: sin a Intensity: I(0) = I„(cos? B)| where B = -sin 0 , a = па -sin O Grating equation (normal incidence): d sin 0 = m order in which the grating is being used, d is the line or groove spacing m = 0,1, 2,3,... (maxima), where m is the
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