The equation and enthalpy change for the reaction between D(g) and F2(g) are given below. D(g) + 2 F2(g) → DF,(g) AH° = -250 kJ/mol,zn (f) If 0.50 mol of DF4(g) is produced when equimolar amounts of D(g) and F2(g) react, how much heat is released?

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An unknown gas, D, reacts with fluorine gas to form the compound DF4(g), as represented by the following equation.
D(g) + 2 F2(9) → DF4(9)
A series of experimental trials were performed at 600°C to determine the rate law expression for the reaction. Data from the trials are shown below.
Initial Pp
Initial PF2
Initial Rate of Appearance of DF,(9)
(torr)
(torr)
(torr/min)
Trial 1
1500
1500
5.00 x 10–3
Trial 2
3000
1500
10.0 x 10-3
Trial 3
1500
3000
20.0 x 10–3
Transcribed Image Text:An unknown gas, D, reacts with fluorine gas to form the compound DF4(g), as represented by the following equation. D(g) + 2 F2(9) → DF4(9) A series of experimental trials were performed at 600°C to determine the rate law expression for the reaction. Data from the trials are shown below. Initial Pp Initial PF2 Initial Rate of Appearance of DF,(9) (torr) (torr) (torr/min) Trial 1 1500 1500 5.00 x 10–3 Trial 2 3000 1500 10.0 x 10-3 Trial 3 1500 3000 20.0 x 10–3
The equation and enthalpy change for the reaction between D(g) and F2(g) are given below.
D(g) + 2 F2(g) → DF,(g) AH° = -250 kJ/mol,zn
(f) If 0.50 mol of DF4(g) is produced when equimolar amounts of D(g) and F2(g) react, how much heat is released?
Transcribed Image Text:The equation and enthalpy change for the reaction between D(g) and F2(g) are given below. D(g) + 2 F2(g) → DF,(g) AH° = -250 kJ/mol,zn (f) If 0.50 mol of DF4(g) is produced when equimolar amounts of D(g) and F2(g) react, how much heat is released?
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