The enthalpy of decomposition of NO₂Cl is -114.0 kJ. Use the following data to calculate the heat of formation of NO₂Cl from N₂, O2, and Cl₂: NO₂Cl(g) N₂(g) + O₂(g) →→→ NO₂(g) N₂(g) + O₂(g) + Cl₂ (8) - → (g) → NO₂ (8) + Cl₂ (8) NO₂C1 AH rxn=-114.0 kJ AH=+33.2 kJ AH°f=?

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The enthalpy of decomposition of NO₂Cl is –114.0 kJ. Use the following data to calculate the heat of formation of NO₂Cl from N₂, O₂, and Cl₂:

| Reaction                                                                 | Enthalpy Change (ΔH)                  |
|--------------------------------------------------------------------------|---------------------------------------|
| NO₂Cl(g) → NO₂(g) + ½ Cl₂(g)                                             | ΔH°ₓₙ = –114.0 kJ                     |
| ½ N₂(g) + O₂(g) → NO₂(g)                                                 | ΔH°ᶠ = +33.2 kJ                       |
| ½ N₂(g) + O₂(g) + ½ Cl₂(g) → NO₂Cl(g)                                    | ΔH°ᶠ = ?                              |

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Calculate the heat of formation (ΔH°ᶠ) for NO₂Cl using the given reaction data. Enter your answer in the provided text box.

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Transcribed Image Text:The enthalpy of decomposition of NO₂Cl is –114.0 kJ. Use the following data to calculate the heat of formation of NO₂Cl from N₂, O₂, and Cl₂: | Reaction | Enthalpy Change (ΔH) | |--------------------------------------------------------------------------|---------------------------------------| | NO₂Cl(g) → NO₂(g) + ½ Cl₂(g) | ΔH°ₓₙ = –114.0 kJ | | ½ N₂(g) + O₂(g) → NO₂(g) | ΔH°ᶠ = +33.2 kJ | | ½ N₂(g) + O₂(g) + ½ Cl₂(g) → NO₂Cl(g) | ΔH°ᶠ = ? | **Instructions:** Calculate the heat of formation (ΔH°ᶠ) for NO₂Cl using the given reaction data. Enter your answer in the provided text box. **Interactive Elements:** - "See Periodic Table" button to reference chemical elements. - "See Hint" button for additional guidance. **User Input:** Provided space to enter the calculated value in kilojoules (kJ).
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