The enthalpy of decomposition of NO₂Cl is -114.0 kJ. Use the following data to calculate the heat of formation of NO₂Cl from N₂, O2, and Cl₂: NO₂Cl(g) N₂(g) + O₂(g) →→→ NO₂(g) N₂(g) + O₂(g) + Cl₂ (8) - → (g) → NO₂ (8) + Cl₂ (8) NO₂C1 AH rxn=-114.0 kJ AH=+33.2 kJ AH°f=?
The enthalpy of decomposition of NO₂Cl is -114.0 kJ. Use the following data to calculate the heat of formation of NO₂Cl from N₂, O2, and Cl₂: NO₂Cl(g) N₂(g) + O₂(g) →→→ NO₂(g) N₂(g) + O₂(g) + Cl₂ (8) - → (g) → NO₂ (8) + Cl₂ (8) NO₂C1 AH rxn=-114.0 kJ AH=+33.2 kJ AH°f=?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Transcribed Image Text:The enthalpy of decomposition of NO₂Cl is –114.0 kJ. Use the following data to calculate the heat of formation of NO₂Cl from N₂, O₂, and Cl₂:
| Reaction | Enthalpy Change (ΔH) |
|--------------------------------------------------------------------------|---------------------------------------|
| NO₂Cl(g) → NO₂(g) + ½ Cl₂(g) | ΔH°ₓₙ = –114.0 kJ |
| ½ N₂(g) + O₂(g) → NO₂(g) | ΔH°ᶠ = +33.2 kJ |
| ½ N₂(g) + O₂(g) + ½ Cl₂(g) → NO₂Cl(g) | ΔH°ᶠ = ? |
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