The employee benefits manager of a large public university would like to estimate the proportion of full-time employees who prefer adopting the first (plan A) of three available health care plans in the next annual enrollment period. A random sample of the university’s employees and their tentative health care preferences are given in the file Healthcare.xlsx below. Calculate a 88% confidence interval for the proportion of all the university’s employees who favor plan A. What are the values of lower limit and upper limit? Round your answer to 3 decimal places.
The employee benefits manager of a large public university would like to estimate the proportion of full-time employees who prefer adopting the first (plan A) of three available health care plans in the next annual enrollment period. A random sample of the university’s employees and their tentative health care preferences are given in the file Healthcare.xlsx below. Calculate a 88% confidence interval for the proportion of all the university’s employees who favor plan A. What are the values of lower limit and upper limit? Round your answer to 3 decimal places.
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter5: Factoring Polynomials
Section5.1: Factoring Integers
Problem 3E
Related questions
Question
The employee benefits manager of a large public university would like to estimate the proportion of full-time employees who prefer adopting the first (plan A) of three available health care plans in the next annual enrollment period. A random sample of the university’s employees and their tentative health care preferences are given in the file Healthcare.xlsx below. Calculate a 88% confidence interval for the proportion of all the university’s employees who favor plan A. What are the values of lower limit and upper limit? Round your answer to 3 decimal places.
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143
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144
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33
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Transcribed Image Text:Employee
1
2
3
4
5
=
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=
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-
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=
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-
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22
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24
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=
26
27
28
29
30
31
34
32
34
33
39
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EY
35
39
36
DU
37
3.8
30
39
53
40
TU
41
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10
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46
TU
47
48
TO
49
12
50
DU
51
51
52
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55
56
57
58
59
60
61
Z
62
63
64
65
66
67
68
69
70
71
72
73
74
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Classification
1
1
2
3
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1
2
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3
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2
2
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