The elementary, irreversible, organic liquid-phase reaction A+ B⇒C is carried out adiabatically in a flow reactor. An equal molar feed in A and B enters at 27°C, and the volu- metric flow rate is 2 dm³/s and CA0 = 0.1 kmol/m³. H(273 K)=-41 kcal/mol Сра = Additional information: HÅ(273 K) = -20 kcal/mol, Hg (273 K) = -15 kcal/mol, CPB = 15 cal/mol. K СРС = 30 cal/mol. K k = 0.01 dm³ mol·s at 300 K E = 10,000 cal/mol PFR (a) Plot and then analyze the conversion and temperature as a function of PFR volume up to where X=0.85. Describe the trends. (b) What is the maximum inlet temperature one could have so that the boiling point of the liquid (550 K) would not be exceeded even for complete conversion? = (c) Plot the heat that must be removed along the reactor (2) vs. V) to maintain isothermal operation. (d) Plot and then analyze the conversion and temperature profiles up to a PFR reactor volume of 10 dm³ for the case when the reaction is reversible with Kc 10 m³/kmol at 450 K. Plot the equilibrium conversion profile. How are the trends different than part (a)? (Ans.: When V = 10 dm³ then X=0.0051, Xeq = 0517) CSTR (e) What is the CSTR volume necessary to achieve 90% conversion?

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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The elementary, irreversible, organic liquid-phase reaction
A+ B⇒C
is carried out adiabatically in a flow reactor. An equal molar feed in A and B enters at 27°C, and the volu-
metric flow rate is 2 dm³/s and CA0 = 0.1 kmol/m³.
H(273 K)=-41 kcal/mol
Сра
=
Additional information:
HÅ(273 K) = -20 kcal/mol, Hg (273 K)
= -15 kcal/mol,
CPB
= 15 cal/mol. K
СРС
= 30 cal/mol. K
k = 0.01
dm³
mol·s
at 300 K
E =
10,000 cal/mol
PFR
(a) Plot and then analyze the conversion and temperature as a function of PFR volume up to where
X=0.85. Describe the trends.
(b) What is the maximum inlet temperature one could have so that the boiling point of the liquid
(550 K) would not be exceeded even for complete conversion?
=
(c) Plot the heat that must be removed along the reactor (2) vs. V) to maintain isothermal operation.
(d) Plot and then analyze the conversion and temperature profiles up to a PFR reactor volume of 10 dm³
for the case when the reaction is reversible with Kc 10 m³/kmol at 450 K. Plot the equilibrium
conversion profile. How are the trends different than part (a)? (Ans.: When V = 10 dm³ then
X=0.0051, Xeq = 0517)
CSTR
(e) What is the CSTR volume necessary to achieve 90% conversion?
Transcribed Image Text:The elementary, irreversible, organic liquid-phase reaction A+ B⇒C is carried out adiabatically in a flow reactor. An equal molar feed in A and B enters at 27°C, and the volu- metric flow rate is 2 dm³/s and CA0 = 0.1 kmol/m³. H(273 K)=-41 kcal/mol Сра = Additional information: HÅ(273 K) = -20 kcal/mol, Hg (273 K) = -15 kcal/mol, CPB = 15 cal/mol. K СРС = 30 cal/mol. K k = 0.01 dm³ mol·s at 300 K E = 10,000 cal/mol PFR (a) Plot and then analyze the conversion and temperature as a function of PFR volume up to where X=0.85. Describe the trends. (b) What is the maximum inlet temperature one could have so that the boiling point of the liquid (550 K) would not be exceeded even for complete conversion? = (c) Plot the heat that must be removed along the reactor (2) vs. V) to maintain isothermal operation. (d) Plot and then analyze the conversion and temperature profiles up to a PFR reactor volume of 10 dm³ for the case when the reaction is reversible with Kc 10 m³/kmol at 450 K. Plot the equilibrium conversion profile. How are the trends different than part (a)? (Ans.: When V = 10 dm³ then X=0.0051, Xeq = 0517) CSTR (e) What is the CSTR volume necessary to achieve 90% conversion?
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