The electric field at a distance of 2 m from a source charge is 8 10^4 V/m. What is the field at a distance of 4m? Choose one or more alternatives: (a) 2 10^4 V/m (b) 10^4 V/m (c) 4 10^4 V/m (d) 16 10^4 V/m
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- An electron is placed at rest in an electric field of 510 N/C. Which of the followings is the speed of the electron 47.0 ns after being released? ( e = 1,6 × 10-19C,e, = 8,85 × 10-12c²/N.m², mej= 9,11× 10-31kg, m, = 1,67 × 10-27kg) Your answer: O A)1.4 x 105 m/s O B) 0.8 x 106 m/s O ) 0.3 x 104 m/s O D) 2.6 x 106 m/s O E)4.2 x 106 m/sCalculate the work required to bring a charge of 5.9×10−95.9×10−9 C from infinity to a point 28.7 cm from a charge of 0.0390.039 μμC in vacuum. Use the value of Coulomb's constant ke=14πε0=9×109ke=14πε0=9×109 m/F. Provide your answer in units of 10−610−6 J: for example, if your answer is 3.6×10−63.6×10−6, then enter 3.6 as your answer.What is the electric field at a point 0.200 m to the right of a +1.50*10^-8 C charge? Include a + or - sign to indicate the direction of the field. (Unit = N/C)
- What is the electric force between an electron and proton when they are separated by a distance of 1.5*10^-3 m?An negative point charge Q = - (1.000x10^0) µC is located at the origin. An electron is initially placed at at distance (2.8000x10^-1) m from Q. The initial velocity of the electron is zero. Under the electric force, the electron accelerates and moves to its final location, (9.40x10^-1) m from Q. What is the final kinetic energy of the electron? (assume there is no other forces on the electron) Give your answer in the unit of J with 3 s.f. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 AnswerAn electron is launched from the surface of a charged sphere of diameter 5.90 cm. If the sphere has been charged to 9.90 nC what is the escape velocity of the electron? 1.23×107 m/s 3.26×107 m/s 7.75×107 m/s 8.10×1012 m/s