An electron is to be accelerated in a uniform electric field having a strength of 1.12x What energy in keV is given to the electron if it is accelerated through 0.624m? 106 V m
An electron is to be accelerated in a uniform electric field having a strength of 1.12x What energy in keV is given to the electron if it is accelerated through 0.624m? 106 V m
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem Statement:**
An electron is to be accelerated in a uniform electric field having a strength of \(1.12 \times 10^6 \, \frac{V}{m}\).
**Question:**
What energy in \(keV\) is given to the electron if it is accelerated through \(0.624 \, m\)?
**Explanation:**
To find the energy given to an electron in a uniform electric field, you can use the formula:
\[ \text{Energy (eV)} = q \times E \times d \]
Where:
- \(q\) is the charge of the electron (\(1.6 \times 10^{-19}\, C\))
- \(E\) is the electric field strength (\(1.12 \times 10^6 \, \frac{V}{m}\))
- \(d\) is the distance (\(0.624 \, m\))
(Note: To convert electron volts (eV) to kilo-electron volts (keV), divide by \(1000\).)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb854e95b-6f91-4ea9-9e99-ab6ba7352139%2F4193c1fd-53e4-4158-8eef-bc16f59a123a%2Fa07ly3j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
An electron is to be accelerated in a uniform electric field having a strength of \(1.12 \times 10^6 \, \frac{V}{m}\).
**Question:**
What energy in \(keV\) is given to the electron if it is accelerated through \(0.624 \, m\)?
**Explanation:**
To find the energy given to an electron in a uniform electric field, you can use the formula:
\[ \text{Energy (eV)} = q \times E \times d \]
Where:
- \(q\) is the charge of the electron (\(1.6 \times 10^{-19}\, C\))
- \(E\) is the electric field strength (\(1.12 \times 10^6 \, \frac{V}{m}\))
- \(d\) is the distance (\(0.624 \, m\))
(Note: To convert electron volts (eV) to kilo-electron volts (keV), divide by \(1000\).)
Expert Solution
Step 1
Given data:
An electron is accelerated in uniform electric field
Electric field (E) = 1.12×106 V/m
Distance (d) = 0.624 m
Required:
The energy given to electron in keV
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