A proton (mass = 1.67 x 10-27 kg, charge 1.60 x 10-19 C) moves from point A to point B under the influence of an electrostatic force only. At point A the proton moves with a speed of 50 km/s. At point B the speed of the proton is 81.2 km/s. Determine the potential difference V-V (in units of volts). Select one: O A. -21.36 O B. 20.95 OC. 16.04 OD. 2.19 OE. -33.64

A proton (mass = 1.67 x 10-27 kg, charge 1.60 x 10-19 C) moves from point A to point B under the influence of an electrostatic force only. At point A the proton moves with a speed of 50 km/s. At point B the speed of the proton is 81.2 km/s. Determine the potential difference V-V (in units of volts). Select one: O A. -21.36 O B. 20.95 OC. 16.04 OD. 2.19 OE. -33.64

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: Multiple-Concept Example 4 deals with the concepts that are important in this problem. As…

Q: What is the electric potential, in volts, due to the proton on an electron in an orbit with radius…

Q: A proton moves from C to B in a uniform electric field of 5 x 10 ^3 N/C, as shown in the following…

A: Potential Energy in electrostatic is the energy required to move a charged particle in a electric…

Q: Oppositely charged parallel plates are separated by 6.06 mm. A potential difference of 600 V exists…

Q: |In nuclear fission, a nucleus splits roughly in half. A. What is the potential 4.00 x 10-14 m from…

A: Charge on fragment, Q = 50 protons = 50×(1.6×10-19) = 80×10-19 C Distance from fragment, r = 4×10-14…

Q: The speed of an electron moving along the y axis increases from 4.45 -10 m/s at y = 10.0 cm to 7.75…

A: a) As per the conservation law of energy, Here, E, K, U, m, v, q, and V represent the electron’s…

Q: Two particles with Q1 = 48 µC and Q2 = 91 µC are initially separated by a distance of 2.2 m and then…

A: Given : Charges Q1 = 48 µC = 48 x 10-6 C and Q2 = 91 µC = 91 x 10-6 C Distance d1 = 2.2m ; Final…

Q: A uniform electric field of magnitude 280 V/m is directed in the positive x direction. A +14.0 µC…

Q: A positive charge q1 = 3.24 nC is located at a point on the x-axis a distance 49.3 cm from the…

Q: A proton (mass 1.67 x 10-27 kg, charge 1,60 x 10-19 C) moves from point A to point B under the…

A: Given data: Charge, q = 1.60 ×10-19 C Mass, m= 1.67 ×10-27 Kg speed at point B vB= 97.4 Km/s = 97400…

Q: An electron that is initially 53 cm away from a proton is displaced to another point. If the change…

A: Given: Initial distance ri=53 cm, Change in electric potential energy ∆PE=3×10-28J. Required: Final…

Q: alpha particle (m = 6.7 × 10−27 kg, q = +3.2 × 10−19 C) has a speed of 30 km/s at point A and moves…

Q: An ion accelerated through 180.00 V has its potential energy decreased by potential energy of 5.76…

Q: A proton is released from rest at the origin in a uniform electric field in the positive x direction…

Q: Oppositely charged parallel plates are separated by 4.97 mm. A potential difference of 600 V exists…

Q: A particle with charge 8.75 x 10-13 C moves a distance d = 0.30 m in a straight line between points…

Q: Oppositely charged parallel plates are separated by 4.79 mm. A potential difference of 600 V exists…

A: (a) The electric field can be given as E=V/d=600/(4.79*10-3)=1.25*105N/C (b) Force acting on the…

Q: The drawing shows a square, each side of which has a length of L = 0.250 m. Two different positive…

Q: A particle of mass 6 × 10−5 kg and charge 6 µC moves downward from point A to point B a distance of…

A: The expression for the work done on a charged particle is written as, Here, q and ΔV represent the…

Q: The potential difference between two parallel plates is 598 V. An alpha particle with mass of…

Q: What is the value of the electrostatic potential at a distance of 0.53 Å (Angstroms) from a proton?…

Q: An electron has an initial speed of 3.0 × 106 m/s. What potential difference is required to bring…

Q: 5. A uniform electric field of magnitude 250 V/m is directe 112.0-µC charge moves from the origin to…

A: Given: A uniform charge of Magnitude 250 V/m is directed in positive x direction, A +112.0μC charge…

Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

A proton (mass = 1.67 x 10-2 kg, charge = 1.60 x 10-19 C) moves from point A to point B under the influence of an
electrostatic force only. At point A the proton moves with a speed of 50 km/s. At point B the speed of the proton is 81.2
km/s. Determine the potential difference V-V (in units of volts).
Select one:
O A. -21.36
ОВ. 20.95
OC. 16.04
O D. 2.19
O E. -33.64

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

As an electron moves through a region of space, its speed decreases from 9.60 × 106 m/s to 2.10 × 106 m/s. The electric force is the only force acting on the electron. Across what potential difference did the electron travel?
A proton (mass = 1.67 × 10-27 kg, charge = 1.60 × 10-19 C) moves from point A to point B under the influence of an electrostatic force only. At point A the proton moves at a speed of 50 km/s. At point B the speed of the proton is 60 km/s. Determine the potential difference V₂ - V₁.
The electric potential difference between the ground and a cloud in a particular thunderstorm is 9.9 × 109 V. What is the magnitude of the change in the electric potential energy of an electron that moves between the ground and the cloud?
Oppositely charged parallel plates are separated by 3.71 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? N/C (b) What is the magnitude of the force on an electron between the plates? (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.00 mm from the positive plate?
A proton (mass = 1.67 x 10-27 kg, charge = 1.60 x 10-19 C) moves from %3D point A to point B under the influence of an electrostatic force only. At point A the proton moves with a speed of 50 km/s. At point B the speed of the proton is 87.8 km/s. Determine the potential difference VB-VA (in units of volts). Select one: O A. 20.41 O B. -42.81 OC. -27.18 OD. 2.15 E. 26.66
Two particles with charges +4e and -7e are initially very far apart (effectively an infinite distance apart). They are then fixed at positions that are 7.43 x 10-12 m apart. What is EPE final - EPEinitial, which is the change in the electric potential energy? Number p. Units
Suppose an electron is released from rest in a uniform electric field whose magnitude is 6.30 x 10³ V/m. (a) Through what potential difference will it have passed after moving 1.00 cm? 2.21*10**-53 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. V (b) How fast will the electron be moving after it has traveled 1.00 cm? m/s
Oppositely charged parallel plates are separated by 5.09 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? (b) What is the magnitude of the force on an electron between the plates? (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.18 mm from the positive plate?
A particle of mass 3 × 10−5kg and charge1 µC moves downward from point A to pointB a distance of 3 m in the earth’s gravitational field. The kinetic energy of the particledecreases by 3.6 mJ during this movement.What is the potential difference VB − VA?The acceleration of gravity is 9.8 m/s2.Answer in units of kV.