The drug Eliquis (apixaban) is used to help prevent blood clots in certain patients. In clinical trials,among 5924 patients treated with Eliquis, 153 developed the adverse reaction of nausea (based on datafrom Bristol-Myers Squibb Co.). Construct a 99% confidence interval for the proportion of adversereactions.

It is given that Sample size n = 5924 Number of patients with adverse reaction, X = 153 Confidence…

Answered: The drug Eliquis (apixaban) is used to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A soft drink company asked you to conduct a survey on consumer preference on their soft drink product "Papsi-Cola" in Metro Manila. Based on your survey, 340 out of 500 people preferred the soft drink "Papsi Cola". a What is the best point estimate for the true proportion of consumers preferring Papsi-Cola in Metro Manila? Construct a 95% confidence interval for the proportion of consumers in Metro Manila that prefer "Papsi-Cola". If more than 60% of the consumers prefer Papsi-Cola, the company will continue the production of the soft drink? Based on your findings, should you advise the company to continue the production of "Papsi-Cola"?
It is being desired to estimate the average daily emission, in tons, of sulfur oxides by a large industrial plant. If n=40, x-=10,6 tons and s=5.51 tons. Construct a 95 percent large-sample confidence interval for the plant’s true average daily emission of sulfur oxides.
Apple Computer believed that 36 percent of its smartphone customer own the most recent model of iPhone (Ho). To test this hypothesis, it gathered customer data using a CRM software. The results indicated that only 30 percent of the iPhone users owned iPhone 11, the most recent model. Assume that this percentage value was based on a sample of 300 users. Test its hypothesis using 95% confidence level.
A poll was conducted to determine the popularity of a 3D game creation software that was targeted to be launched in three months. Online interviews with 1200 young adults were conducted which revealed that 45% said they would purchase the new software. The margin of error was ±3 percentage points. What is the needed sample size to obtain a 96% confidence interval estimate of the percentage of the targeted young adults who will purchase the new software by allowing the same level of margin of error?
A study was carried out on the effectiveness of Reiki therapeutic touch to manage pain in cancer patients. Pain was assessed twice for each of the 14 cancer patients: once before and once after Reiki touch therapy. For each of the 14 subjects, the difference between each pair of pain scores was recorded (difference = after - before). The 14 differences have a mean of -1.86 and a standard deviation of 1.69. 1. Compute a 95% confidence interval for the true population mean change in pain scores. (give answers to 4 places past decimal) lower bound: Submit Answer Tries 0/99 upper bound: 2. Which one of the following is the correct interpretation of the confidence interval in part 1 above? O The most likely mean difference in pain score for any cancer patient is -1.86. O There is a 95% chance that the above confidence interval will contain the true mean difference. O The true mean difference in pain score in all cancer patients is -1.86. O With repeated sampling, your confidence interval…
A survey by the society of Human Resource Management asked 350 job seekers why employees change jobs so frequently. The answer selected most (126 times) was "higher compensation elsewhere" as the reason for changing jobs. Then the 95% confidence interval estimate for the population proportion of job seekers who would select "higher compensation elsewhere" as the reason for changing jobs is approximately.
The prevalence rate of osteoporosis among women were measured in a survey, p(%) = 25.3 SE (p) = 1.8 calculate the upper bound of 95% confidence interval
A car manufacture produces a new car that advertises an average of 30 MPG. The distribution of MPG of cars is normally distributed. The manufacturer will test 30 cars off the assembly line to find a confidence interval of the average MPG of their new vehicle to determine if it is close to 30. The average MPG of the 30 cars is 31.2 gallons with a standard deviation of 2 gallons. Find a 95% confidence interval for the average MPG of the new vehicle. (30.45, 31.95) (30.48, 31.92) O (31.18, 31.22) O The sample size is too small to compute a confidence interval.
Kmart decided to inventory all of its furniture stock for a year end evaluation. At that time there were 768 items of furniture. A random sample of 40 items of furniture were selected for audit, with sample mean=$249.06 and SD=$92.58. Construct a 95% confidence interval estimate of the total value of furniture stock for year end.
A survey about allergic reactions revealed that 84 out of randomly selected 158 people exhibit allergic symptoms. The percentage of the whole country is believed to be 25% for such allergic symptoms. Find the test statistic for hypothesis testing at right tail. (Sensitivity 0.00)
The Consumer Product Safety Commission regulates products sold for use with children. An investigator is tasked with determining whether a male child will get sick after being exposed to a certain brand of house paint than a female child. Data was collected that on 1854 children between the ages one and four, all of whom were exposed to the same brand of house paint. 985 were boys, while 869 were girls. Determine a 95% confidence interval for the difference in proportions of male and female children, ages one to four, who will get sick. Round to four decimal places.With % confidence, it can be concluded that the difference in proportions of between male and female children, ages one to four, who get sick after being exposed to this brand of house paint is (p1 - p2) is between BLANK and BLANK .
A study was done to determine whether there is a relationship between snoring and the risk of heart disease. Among 1,105 snorers in the study, 85 had heart disease, while only 21 of 1,379 nonsnorers had heart disease. In USE SALT (a) Determine a 95% confidence interval that estimates p, - p2 difference in proportions of snorers and nonsnorers who have heart disease. (Let p, be the proportion of snorers and p, be the proportion of nonsnorers. Round your answers to three decimal places.) |-0.079 X to -0.045

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