The direction of the magnetic field due to moving proton and the force direction is given out of the screen. Fout of screen xx x x x x x x x x x x E.
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- Problem #4 A) A proton is moving with a speed of 3e6 m/s. What is the magnitude of the magnetic field created by this moving proton at a distance of 4.8 nm? B) If the proton enters a uniform magnetic field of strength 8.3 uT, what is the magnitude of the magnetic force on the proton? (The velocity of the proton is perpendicular to the direction of the magnetic field.) C) The proton will begin moving uniform circular motion due to this magnetic force. What is the radius of this circular motion?In what direction is the force F→ exerted by the magnetic field on the electron? In what direction is the force exerted by the magnetic field on the electron? F→ is parallel to the wire and points upward. F → is parallel to the wire and points downward. F→ is perpendicular to the wire and points toward the wire. F → is perpendicular to the wire and points away from the wire. If the magnetic field of the wire is 3.5×10−4 T and the electron moves at 4.0×106 m/s , what is the magnitude F of the force exerted on the electron?In a CRT electrons are accelerated from rest by a potential difference of 1.40x103 V These electrons enter a magnetic field with a strength of 2.20x10-2 T. Assuming the electrons are travelling perpendicular to the field what is the radius of the arc of the deflecting electrons?
- What would be the magnitude and direction of force FB on an electron (q = -e, me = 9.1 x 10-31 kg) shot in the +y direction with a speed of 4.7 x 106 m/s in a uniform magnetic field B = 2.6 x 10-4 T along +y direction ? FB = 2.4 x 10-16 N away from us, towards the plane of the screen FB = 0.00 N so will maintain its velocity. FB = 1.95 x 10-16 N toward us, away from the plane of the screen FB = 4.9 x 10-11 N away from us, towards the plane of the screenFind the direction of the magnetic field acting on a positively charged particle moving in the various situations shown if the direction of the magnetic force acting on it is as indicated.An electron at point A has speed v0 = 1.41 x 106 m/s. Find:- The magnitude and direction of the magnetic field- The time required in nanosecondsfor the electron to follow the semicircular path form A to B.
- The vector velocity will always be to the right and the magnetic field will be into the screen or out of the screen. The angle is 90 degrees. Determine the magnitude of the magnetic force and the radius of the curvature. Will the charge be deflected to the left, or to the right or not at all when it enters the magnetic field? Strength of magnetic Field (B): 6.0T Mass of charge (m): 5.0x10-25 kg Charge (q): 4.0 x 10-16 C Velocity (v): 5.0 x 106 m/sA particle of mass m carrying a negative charge q passes through a perpendicular magnetic field B al speed v. as shown below. The radius of its circular path while it is within the magnetic field is r. (see diagram) Which of the following is equal to the speed, r. of the particle? A) qr/mB B) qBr/m C) qB/rm D) m/qBrA beam of electrons is simultaneously influenced by an homogeneous electric field of 15600 V/m and by a homogeneous magnetic field of 4.62 x 10-3 T. Assume that both fields are perpendicular to the electron beam and to each other. Both fields have to be oriented such that they produce no deflection of the electron beam. a) Draw the relative orientations of the vectors v, E, and B and also the forces of FE and FB .b) Determine the speed of the electrons such that there is no deflection of the electron beam. c) When the electric field is switched off, what is the radius and the period of the electron orbit?
- A-4.80 uC charge is moving at a constant speed of 6.80 x 105 m/s in the +x-direction relative to a reference frame. At the instant when the point charge is at the origin, what is the magnetic field vector it produces at the following points a point (x 0.500 m, y = 0.500 m, z 0) Select one: B = -1.29x10-77 B = -4.62x10-7 R B = -7.15x10-7 R B = -2.12x10-7↑ B = 3.17x10 6-27 kg is The charge of an electron and a proton are both equal to q = 1.602 x 10-19 but the mass of a proton mp = 1.673 x 10 much larger than the mass of an electron me = 9.11 x 10-31 kg. If a proton and an electron move at the same speed in a circular path in a uniform magnetic field, what is the ratio of the radius of the proton's circular path r, to the radius of the electron's circular path Image size: s ML Max re. In other words what is rp/re? Note: the picture of the circular paths for the electron and proton are not drawn to scale. メ re Please enter a numerical answer below. Accepted formats are numbers or "e" based scientific notation e.g. 0.23, -2, 1e6, 5.23e-8In a CRT electrons are accelerated from rest by a potential difference of 1.40x10³V These electrons enter a magnetic field with a strength of 2.20x102 T Assuming the electrons are traveling perpendicular to the field what id the radius of the arc of the deflected electrons?