A-4.80 pC charge is moving at a constant speed of 6.80 x 10 m/s in the +x-direction relative to a reference frame. At the instant when the point charge is at the origin, what is the magnetic field vector it produces at the following points a point (x = 0.500 m, y = 0.500 m, z 0) %3D
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- *Chapter 28, Problem 015 GO In the figure, a conducting rectangular body of dimensions dx = 9.19 m, dy = 3.06 m, and dz = 1.94 m moves at constant velocity V = (16.5 m/s)i through a uniform magnetic field (25.9 mT)j. (a) %3D What is the resulting electric field within the body, in unit-vector notation? (b) What is the resulting potential difference across the body? d, de (a) Number Units (b) Number UnitsA charge particle is undergoing uniform circular motion due to a constant magnetic field. Which of the following will increase the radius of the particle's circular path? A. decreasing its mass B. increasing its charge C. decreasing the magnitude of the ratio of its mass to charge D. increasing the magnitude of the ratio of magnetic field strength to speed E. decreasing the magnetic field strength.Consider the current-carrying wire shown in the figure. The current creates a magnetic field at the point P, which is the center of the arc segment of the wire. If 0 = 30.0°, the radius of the arc is 0.800 m, and the current is 5.00 A, what are the magnitude (in nT) and direction of the field produced at P? magnitude 3.272*10**-7X Did you forget to convert from T to nT? nT
- A hydroxide ion (OH−) in a glass of water has an average speed of about 600 m/s. A. Determine the magnitude of the electrical force between the hydroxide ion (charge -e) and a positive ion (charge +e) that is 1.0×10−8 m away (about the separation of 30 atoms). B. Determine the magnitude of the maximum magnetic force that Earth's 3.0×10−5 T magnetic field can exert on the ion.A charged particle moves through a velocity selector at constant velocity. The velocity selector is configured with "crossed" electric and magnetic fields of magnitude E = 1.50 x 104 N/C and B = 0.4 T. %3D Hint a. What is the velocity of the charged particle? Velocity of the charged particle is x 104 m/s. b. When the electric field is turned off, the charged particle travels in a circular path of radius 6 mm, as it travels through the magnetic field (still at B = 0.4 T). What is the mass-to-charge ratio of the particle? Hint for (b) Mass-to-charge ratio of the part is kg/C. (Use the "E" notation to enter your answer in scientific notation. For example, to enter 3.14 × 10´ 12".) - 12 enter "3.14E-Two long, parallel wires are separated by 2.8 m. Each wire has a 32-A current, but the currents are in opposite directions. A. Determine the magnitude of the net magnetic field midway between the wires. B. Determine the magnitude of the net magnetic field at a point 1.4 m to the side of one wire and 4.2 m from the other wire. The point is in the same plane as the wires.