c. Determine the angle that the net magnetic field vector makes with the+z-axis at the point midway between the two wires. ### Problem StatementTwo long wires are oriented so that they are perpendicular to each other. At their closest, they are 20.0 cm apart, as shown in the figure below. The top wire carries a current of 20.0 A out of the page, and the bottom wire carries a current of 12.0 A to the right. (Note: Take the +x-axis to be to the right, the +y-axis to be up, and the +z-axis to be out of the page.)**Figure Explanation:**- The figure shows two wires, one oriented horizontally (the bottom wire), and the other vertically positioned above the bottom wire.- The top wire has a current \( I_T = 20.0 \, A \) directed out of the page.- The bottom wire has a current \( I_B = 12.0 \, A \) directed to the right.- The distance between the two wires is given as 20.0 cm.- There is a point of interest located midway between the two wires along the vertical line or along the y-axis. The distance from each wire to this midpoint is 10.0 cm.**Questions:**(a) What is the magnitude and direction (right, left, up, down, into the page, or out of the page) of the magnetic field at a point midway between the two wires due to the current in the top wire?(b) What is the magnitude and direction (right, left, up, down, into the page, or out of the page) of the magnetic field at a point midway between the two wires due to the current in the bottom wire?### Illustration:![Diagram of Wires and Magnetic Field Setup](image_url)- *Top Wire*: Current \( I_T = 20.0 \, A \) (out of the page)- *Bottom Wire*: Current \( I_B = 12.0 \, A \) (to the right)- *Separation*: 20.0 cm between wires- *Point of Interest*: Midway between the two wires, at 10.0 cm from each wire.### Solution:(a) *Magnetic Field due to the Top Wire:*To find the magnetic field at the midpoint due to the top wire:- Use the Biot-Savart Law or Ampère's Law.- Calculate the distance from the wire to the midpoint.- Apply

The magnetic field due to a wire is circumferential and its magnitude is given by given by, From…

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