An ion with charge +4e is fired into a magnetic field of B = 2.3 mT. The velocity of the particle is 6.6 x 106 m/s at an angle of 45° from the magnetic field. What is the magnitude of the force this ion will experience? Recall that 1 mT = 10-³ T. You can enter exponential notation as x.yzE-q to represent x.yz x 109 (for example, 5,67 x 10-18 can be entered as 5.67E-18. F = N

An ion with charge +4e is fired into a magnetic field of B = 2.3 mT. The velocity of the particle is 6.6 x 106 m/s at an angle of 45° from the magnetic field. What is the magnitude of the force this ion will experience? Recall that 1 mT = 10-³ T. You can enter exponential notation as x.yzE-q to represent x.yz x 109 (for example, 5,67 x 10-18 can be entered as 5.67E-18. F = N

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A wire carrying 25.5 A current passes between the poles of a strong magnet that is directed at angle 20° to its magnetic field of 0.75 T and experiences a 2.6 N force. What is the length of wire in centimeter?
A 11-cm-long straight wire is parallel with thex axis and carries a current of 1.8 A in the +x direction. The force on this wire due to the presence of a magnetic B is 2.8 N -2.2 N k. Determine the magnetic field B. B = (C field + 2.2 N k. If this wire is rotated so that it is parallel with the y axis with the current in the +y direction, the force on the wire becomes -2.8 N
AN ELECTRON MOVING 8 X 10^3m/s IN A 3.75 T MAGNETIC FIELD EXPERIENCES A MAGNETIC FORCE OF 2.5 X10^-13 N. WHAT ANGLE DOES THE VELOCITY OF THE ELECTRON MAKE WITH THE ELECTRIC FIELD ? THERE ARE TWO ANSWERS
A charge of -8.84 μC is traveling at a speed of 6.02 × 106 m/s in a region of space where there is a magnetic field. The angle between the velocity of the charge and the field is 55.1o. A force of magnitude6.02 × 10-3 N acts on the charge. What is the magnitude of the magnetic field?
A proton is going 28 m/s when it is exposed to a 3 T magnetic field (see below) and begins moving in a circle. Determine the direction of the magnetic force, the radius of the mass of 1.67×10-27 kg. Ignore gravity. motion, and the period (time to complete one orbit). A proton has a charge of 1.6x10-19 C & Direction of magnetic force: Choose direction ✓ ……..…….……………………………………..... Radius= Period = direction of velocity direction of external magnetic field
A proton enters a magnetic field with a speed of v = 0.5231 Mm,whose magnetic flux density B = 0.8946 T. Calculate the force exerted by the magnetic field on the proton. B ** What is the magnetic force on the proton? Fm = N 9 Insert only 3 most significant digits of your answer without rounding. Constant Value Unit 1.6020 × 10-19C
An electron accelerated from rest by a potential difference of 350 V enters a uniform magnetic field such that its velocity is perpendicular to the direction of the magnetic field. The field forces the electron to complete one circular path in 4 us. What is the radius (in m) of the circular path? [m, = 9.11 x 10-31 kg, e =1.6 x10-19 C] 1. O 18.6 2. O1.86 3. 07.1 4. O 10.6 5. 05.3 Copyright o z019, The Hashemite University. All Ftights Reerved 12:59 PM 8/28/2021
A particle (mass = 2.0 mg, charge = –6.0 µC) is moving along the x-axis direction with a velocity of 3.0 km / s. The particle enters a magnetic field of (2.0i + 3.0j + 4.0k) mT. What is the acceleration of the particle?
charge ??=1.6×10−19qp=1.6×10−19 that moves at right angles to the direction of a uniform magnetic field of strength 87.8 mT , if the magnetic force on particle is 4×10−134×10−13 N. Give your answer in km s-1
An electron moves with a speed of 2.5×107 m/sm/s in the directions shown in the figure. A 0.40 TT magnetic field points in the positive x-direction.(Figure 1) A. What is the magnitude of the magnetic force in figure (a)? F= B. What is the direction of the magnetic force in figure (a)? a. +z direction b. -z direction c. +zy direction d. -zy direction C. What is the magnitude of the magnetic force in figure (b)? F = D. What is the direction of the magnetic force in figure (b)? a. +zy direction b. -zy direction c. +z direction d. -y direction
When a -3.2 C charge moves into a magnetic field of strength 6.5 x 10-3 T it experiences a magnetic force of magnitude 7.1 N. Calculate the speed of the charge in m/s.
An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.230 T. If the kinetic energy of the electron is 3.70 x 10-19 J, find the speed of the electron and the radius of the circular path. (a) the speed of the electron 9.02e5 ✔ m/s (b) the radius of the circular path Your response is off by a multiple of ten. um