The diagram shows the all of the forces acting on a body of mass 2.31 kg. The three forces have magnitudes F₁ = 50.6 N, F2 = 20.8 N, and F3 = 75.8 N, with directions as indicted in the diagram, where 0 = 39.6 degrees and p = 30.1 degrees. The dashed lines are parallel to the x and y axes. At t=0, the body is moving at a speed of 7.93 m/s in the positive x direction. ax=-20.45 ax=-20.45 ay = 6.170 Part (a) What is the x component of the acceleration in m/s²? v = 216.7 Part (b) What is the y component of the acceleration in m/s²? Part (c) What is the speed of the body, in m/s, at t = 10.5 s? Part (d) What is the magnitude of the displacement of the body, in meters, between t = 0 and 10.5 s? F F₂ 0 F X
The diagram shows the all of the forces acting on a body of mass 2.31 kg. The three forces have magnitudes F₁ = 50.6 N, F2 = 20.8 N, and F3 = 75.8 N, with directions as indicted in the diagram, where 0 = 39.6 degrees and p = 30.1 degrees. The dashed lines are parallel to the x and y axes. At t=0, the body is moving at a speed of 7.93 m/s in the positive x direction. ax=-20.45 ax=-20.45 ay = 6.170 Part (a) What is the x component of the acceleration in m/s²? v = 216.7 Part (b) What is the y component of the acceleration in m/s²? Part (c) What is the speed of the body, in m/s, at t = 10.5 s? Part (d) What is the magnitude of the displacement of the body, in meters, between t = 0 and 10.5 s? F F₂ 0 F X
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Step 1: Define Newton's second law of motion:
VIEWStep 2: Calculate the net acceleration of the object along the x-direction.
VIEWStep 3: Calculate the net displacement along the x-direction:
VIEWStep 4: Calculate the net acceleration of the object along the y-direction.
VIEWStep 5: Calculate the net displacement along the y-direction:
VIEWStep 6: Find the magnitude of the net displacement:
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