part c please A 20-cm-radius ball is uniformly charged to 53 nCYou may want to review (Page 658)For help with math skills, you may want to review:Volume Calculations for a SphereFor general problem-solving tips and strategies for this topic, you maywant to view a Video Tutor Solution of Charges on a cell membrane.▼What is the ball's volume charge density (C/m³)?Express your answer using two significant figures.P= 1.6x10-6 C/m³Submit Previous Answers✓ CorrectCorrect answer is shown. Your answer 1.58-10-6 = 1.58x10-6 C/m³ was either rounded differently or used arequired for this part.Part BHow much charge is enclosed by spheres of radii 5, 10, and 20 cm?Express your answers using two significant figures. Enter your answers numerically separated by commas.Q5. 10. 20 0.83,6.6,53 nC=Submit Previous Answers✓ CorrectTerm 2: Correct answer is shown. Your answer 6.62 nC was either rounded differently or used a different numbthis part.Part CWhat is the electric field strength at points 5, 10, and 20 cm from the center?Express your answers using two significant figures. Enter your answers numerically separated by commas.——| ΑΣΦEs. E10, E20 190800,47700,11925SubmitPrevious Answers Request AnswerX Incorrect; Try Again?N/C

Answered: Image /qna-images/answer/d4b6798d-b87f-4b01-8745-dce970bdf0d4.jpg

Part C What is the electric field strength at points 5, 10, and 20 cm from the center? Express your answers using two significant figures. Enter your answers numerically separated by commas. 195| ΑΣΦ Es. E10. E20 = 190800, 47700, 11925 Submit Previous Answers Request Answer X Incorrect: Try Again ? N/C

Part C What is the electric field strength at points 5, 10, and 20 cm from the center? Express your answers using two significant figures. Enter your answers numerically separated by commas. 195| ΑΣΦ Es. E10. E20 = 190800, 47700, 11925 Submit Previous Answers Request Answer X Incorrect: Try Again ? N/C

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Part E Find x-component of F = (20.0 N, 36.9° counterclockwise from the positive y-axis). Express your answer with the appropriate units. View Available Hint(s) Fx = Submit Part F Fy= μÃ Submit Value Find y-component of F = (20.0 N, 36.9° counterclockwise from the positive y-axis). Express your answer with the appropriate units. View Available Hint(s) µÅ Units Value ? Units ?
A 2004 Prius with a 150 lb driver and no passengers weighs 3071 lb. The car is initially at rest. Starting at t = 0, a net horizontal force F₂ (t) in the +x-direction is applied to the car. The force as a function of time is given in (Figure 1). The horisontal parts on the graph correspond to 7500 N and 3500 N Figure F, (N) 8000 6000 4000 2000 0 1.00 2.00 3.00 < 1 of 1 4.00 5.00 -t (s) Part A For the time interval t = 0 to t = 4.50 s, what is the impulse applied to the car? Express your answer to two significant figures and include the appropriate units. J = Submit Part B V = μÀ Value O Request Answer What is the speed of the car at t = 4.50 s? Express your answer to two significant figures and include the appropriate units. μA Units Value ? Units ?
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Part A For the step ladder shown in the Figure, sides AC and CE are each 2.7 m long and hinged at C. BD is a 0.71 m long tie rod, installed halfway up the ladder. A 47 kg man climbs 1.65 m along the ladder. Assuming that the floor is frictionless and neglecting the weight of the ladder, find the tension in the tie rod. B O E Submit Answer Tries 0/6 Part B What is the force exerted by the ladder on the floor at A? Submit Answer Tries 0/6 Part C What is the force exerted by the ladder on the floor at E? Submit Answer Tries 0/6
A 65 kg person running at 2.0 m/s jumps onto the skim board at right. The skim board is 50 cm wide and 120 cm long, with an area of 0.60 m². Part A Draw a sketch of this situation. Part B If the person jumps onto the board on sand with a coefficient of friction of f=0.50, what force will resist the forward movement of the board [N]? Recall the friction force is the normal force times the coefficient of friction. Part C Now assume the person jumps onto the board on a 0.50 cm film of fresh water at 30°C. Use Newton's law of viscosity to estimate the force resisting the forward movement of the board.
Two Blocks having mass m=11.0 kg are connected by a light string passing through two pulleys as shown. The block on the left is resting on an inclined plane of angle 0=45.0° . The pulleys and the planes on which the blocks are resting are frictionless. The blocks are released from rest and allowed to move freely. a. Draw the free body diamgrams for each block and then write down newton's second law of motion for each one separately. b. Find the acceleration of the blocks and the tension in the string.
Need help with Part C
Figure B 0.500 m Part C Block A has a mass of mд = 42.0 kg and rests on a flat surface. (Figure 3)The coefficient of static friction between the block and the surface is μA = 0.210. The coefficient of static friction between the rope and the fixed peg B is 0.340. The width of the block is d=0.200 m. Find the greatest mass, mc, that weight C can have such that block A does not move. Express your answer numerically in kilograms to three significant figures. ▸ View Available Hint(s) ΜΕ ΑΣΦ ↓↑ vec mc 30.6 T 0.200 m A 0.300 m Submit Previous Answers 0.400 m- × Incorrect; Try Again; 19 attempts remaining ? kg
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Two ice skaters, with masses of 36.0 kg and 75.0 kg, are at the center of a 40.0 m diameter circular rink. The skaters push off against each other and glide to opposite edges of the rink. Part A If the heavier skater reaches the edge in 20.0 s , how long does the lighter skater take to reach the edge? ΑΣΦ Submit Request Answer