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1. The current I through a long solenoid with n turns per meter and radius 0.30m is changing with time as given by /= sin(120t). The magnetic field inside a solenoid is given by B = nuol where μo is the free space permeability Mo=1.26-10-6 H/m. Because of the varying current, the magnetic field inside the solenoid will also vary, and induce an electric field inside the solenoid according to Faraday's Law. In this problem you will calculate the induced electric field as a function of distance r from the central axis of the solenoid for r. a) Start by determining the magnetic flux through a through a single coil at a time of t= 1.1 s at distance r= 0.28 m from the center of the solenoid if there are, n=105 turns/m?. Hint: Is the angle for the sine function in degrees or radians? B=nuosin(120t) πr²= 1.729-10-66 Tm² b) Next determine the rate of change of the magnetic flux with time B=(nu sin(120t) ²) = 3.904-10-3 dt 3.904-10-3 Tm²/s c) The electic field can then be determined from | E-di|-|-| dl problem means the electric field is constant when integrating around the loop. E at t= 1.1 s at distance r= 0.28 m from the center of the solenoid = 2.072-10-³√ V/m Recall that the symmetry of the

1. The current I through a long solenoid with n turns per meter and radius 0.30m is changing with time as given by /= sin(120t). The magnetic field inside a solenoid is given by B = nuol where μo is the free space permeability Mo=1.26-10-6 H/m. Because of the varying current, the magnetic field inside the solenoid will also vary, and induce an electric field inside the solenoid according to Faraday's Law. In this problem you will calculate the induced electric field as a function of distance r from the central axis of the solenoid for r. a) Start by determining the magnetic flux through a through a single coil at a time of t= 1.1 s at distance r= 0.28 m from the center of the solenoid if there are, n=105 turns/m?. Hint: Is the angle for the sine function in degrees or radians? B=nuosin(120t) πr²= 1.729-10-66 Tm² b) Next determine the rate of change of the magnetic flux with time B=(nu sin(120t) ²) = 3.904-10-3 dt 3.904-10-3 Tm²/s c) The electic field can then be determined from | E-di|-|-| dl problem means the electric field is constant when integrating around the loop. E at t= 1.1 s at distance r= 0.28 m from the center of the solenoid = 2.072-10-³√ V/m Recall that the symmetry of the

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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1. The current I through a long solenoid with n turns per meter and radius 0.30m is changing with time as given by /= sin(120t). The magnetic field inside a solenoid is given by B = nul where μo is the free space permeability Ho=1.26-10-6 H/m. Because of the varying current, the magnetic field inside the solenoid will also vary, and induce an electric field inside the solenoid according to Faraday's Law. In this problem you will calculate the induced electric field as a function of distance r from the central axis of the solenoid for r. a) Start by determining the magnetic flux through a through a single coil at a time of t= 1.1 s at distance r= 0.28 m from the center of the solenoid if there are, n=105 turns/m?. Hint: Is the angle for the sine function in degrees or radians? B = nu sin(120t)₁²= 1.729-10-66 Tm² b) Next determine the rate of change of the magnetic flux with time B=(nu sin(120t) π²²) = 3.904-10-3 Tm²/s dt c) The electic field can then be determined from | E-di|=|d₂| DE.dl= dt problem means the electric field is constant when integrating around the loop. B E at t= 1.1 s at distance r= 0.28 m from the center of the solenoid = Recall that the symmetry of the 2.072-10-3 V/m
Transcribed Image Text:1. The current I through a long solenoid with n turns per meter and radius 0.30m is changing with time as given by /= sin(120t). The magnetic field inside a solenoid is given by B = nul where μo is the free space permeability Ho=1.26-10-6 H/m. Because of the varying current, the magnetic field inside the solenoid will also vary, and induce an electric field inside the solenoid according to Faraday's Law. In this problem you will calculate the induced electric field as a function of distance r from the central axis of the solenoid for r. a) Start by determining the magnetic flux through a through a single coil at a time of t= 1.1 s at distance r= 0.28 m from the center of the solenoid if there are, n=105 turns/m?. Hint: Is the angle for the sine function in degrees or radians? B = nu sin(120t)₁²= 1.729-10-66 Tm² b) Next determine the rate of change of the magnetic flux with time B=(nu sin(120t) π²²) = 3.904-10-3 Tm²/s dt c) The electic field can then be determined from | E-di|=|d₂| DE.dl= dt problem means the electric field is constant when integrating around the loop. B E at t= 1.1 s at distance r= 0.28 m from the center of the solenoid = Recall that the symmetry of the 2.072-10-3 V/m
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