The diagram shows a thin rod of uniform mass distribution pivoted about one end by a pin passing through that point. The mass of the rod is 0.580 kg and its length is 1.80 m. When the rod is released from its horizontal position, it swings down to the vertical position as shown. (a) Determine the speed of its center of gravity at its lowest position in m/s. (b)When the rod reaches the vertical position, calculate the tangential speed of the free end of the rod in m/s. Check your calculations. m/s **Description of Diagram:**The diagram illustrates a thin rod of uniform mass distribution that is pivoted at one end by a pin. The mass of the rod is 0.580 kg, and its length is 1.80 m. When released from its horizontal position, the rod swings down to the vertical position. - The pivot point is shown at the top left end of the rod.- "CG" denotes the center of gravity, located at a distance of \( L/2 \) from the pivot point, where \( L \) is the length of the rod.- An arrow shows the direction of the rod's swing from horizontal to vertical.**Questions:**(a) Determine the speed of its center of gravity at its lowest position in m/s.**Answer Box:** 5.35 ✗*Hint:* Consider the conservation of energy for the center of mass of the rod. What is the relationship between angular and tangential velocities?(b) When the rod reaches the vertical position, calculate the tangential speed of the free end of the rod in m/s.**Answer Box:** 9.51 ✗*Hint:* Check your calculations.**Explanation:**The problem concerns the motion dynamics of a pivoted rod. The goal is to understand the principles of energy conservation and rotational motion (angular and tangential velocities). The rod's gravitational potential energy at its initial position is converted into kinetic energy as it swings to the lowest position.

Answered: Image /qna-images/answer/495e5c88-0549-4205-a6e8-71ba9d629ca1.jpg

Answered: The diagram shows a thin rod of uniform…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Question

The diagram shows a thin rod of uniform mass distribution pivoted about one end by a pin passing through that point. The mass of the rod is 0.580 kg and its length is 1.80 m. When the rod is released from its horizontal position, it swings down to the vertical position as shown.

(a) Determine the speed of its center of gravity at its lowest position in m/s.

(b)

When the rod reaches the vertical position, calculate the tangential speed of the free end of the rod in m/s.

Check your calculations. m/s

**Description of Diagram:**

The diagram illustrates a thin rod of uniform mass distribution that is pivoted at one end by a pin. The mass of the rod is 0.580 kg, and its length is 1.80 m. When released from its horizontal position, the rod swings down to the vertical position.

- The pivot point is shown at the top left end of the rod.
- "CG" denotes the center of gravity, located at a distance of \( L/2 \) from the pivot point, where \( L \) is the length of the rod.
- An arrow shows the direction of the rod's swing from horizontal to vertical.

**Questions:**

(a) Determine the speed of its center of gravity at its lowest position in m/s.

**Answer Box:** 5.35 ✗

*Hint:* Consider the conservation of energy for the center of mass of the rod. What is the relationship between angular and tangential velocities?

(b) When the rod reaches the vertical position, calculate the tangential speed of the free end of the rod in m/s.

**Answer Box:** 9.51 ✗

*Hint:* Check your calculations.

**Explanation:**

The problem concerns the motion dynamics of a pivoted rod. The goal is to understand the principles of energy conservation and rotational motion (angular and tangential velocities). The rod's gravitational potential energy at its initial position is converted into kinetic energy as it swings to the lowest position.

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions