The deflection temperature under load for two different types of plastic pipe is beinginvestigated. Two random samples of 15 pipe specimens are tested, and the deflectiontemperatures observed are as follows (in oF):Туре 1: 206, 188, 205, 187, 194, 193, 207, 185, 189, 213, 192, 210, 194, 178, 205.Туре 2: 177, 197, 206, 201, 180, 176, 185, 200, 197, 192, 198, 188, 189, 203, 192.1. Determine the coefficient of dispersion of each type of plastic pipe.2. Interpret the results.Compare the SDUS of the 10th observation in each type. What conclusion can youmake?

Given the deflection temperatures of two random samples of 15 pipe specimens tested as Type 1…

Answered: The deflection temperature under load…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose that the average salary of health systems professionals is normally distributed with µ=KES 40,000 and σ = KES 10,000. (20 Marks) What proportion of professionals will earn KES 24,800 or less? What proportion of professionals will earn KES 53,500 or more? What proportion of professionals will earn between KES 45,000 and KES 57,000? Calculate the 80th percentile. Calculate the 27th percentile
3. At a land farm, a farmer desired to test the effect of a given fertilizer on soybean production. He chose 24 plots of land of which are equal surface area. He treated 12 plots with the fertilizer and the others were untreated. Otherwise the conditions were the same. The treated plots produced soybean with mean yield 5.1 bushels and a standard deviation of 0.36 bushels, while the untreated plots had mean yield 4.8 bushels and a standard deviation of 0.40 bushels. (a) Can we conclude that there is a significant improvement in soybean production because of the fertilizer if a significance level of 1% is used? (b) What is the P-value of the test?
A paint company has large outlet stores in two cities. Ten samples of the weekly sales (in tons) for the two cities are as follows. City A: n = 10, X10 = 148.5, S1 = = 4.3. City B: n = 10, Y 10 = 144.2, S2 = 3.8. At a = 0.05 level of significance, test if the weekly sales are different. The following ¨answers" have been proposed. (a) The null hypothesis is that the weekly sales are the same and the alternative is that the they are not the same. By using an F test, we reject the null hypothesis. (b) The null hypothesis is that the weekly sales are the same and the alternative is that the they are not the same. By using an F test, we do not reject the null hypothesis. (c) The null hypothesis is that the weekly sales are the same and the alternative is that the they are not the same. By using a i test, we do not reject the null hypothesis. (d) The null hypothesis is that the weekly sales are the same and the alternative is that the they are not the same. By using a i test, we reject the…
Polyunsaturated fatty acids in the diet favorably affect several risk factors for cardiovascular disease. The principal dietary polyunsaturated fat is linoleic acid. Suppose we randomly selected twelve adults for our study. We took their blood pressure measurements (systolic blood pressure) at the start and recorded them for each adult. Then we placed required these adults to consume 23g/day of safflower oil which is high in linoleic acid for four weeks. At the end of the four weeks, we took another systolic blood pressure(SBP) measurement. The paired data is provided below: Subject 1 2 3 4 5 6 7 8 9 10 11 12 Baseline SBP 119.67 100.00 123.56 109.89 96.22 133.33 115.78 126.39 122.78 117.44 111.33 92.39 1-month SBP 117.33 98.78 123.83 107.67 95.67 128.89 113.22 121.56 126.33 110.39 107.00 93.06 Use the appropriate nonparametric test at alpha level of 0.05, to test whether the diet heavy in linoleic acid increases systolic blood pressure (SBP). Use Steps 0-5
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Clothes dried outside smell better than those dried in a dryer because of a process called photolysis. Sunlight breaks down compounds that cause odor. A trained smeller is asked to smell a random sample of 20 towels. The smeller does not know it, but all of the 20 towels have been dried in the sun. The smeller is blindfolded and is not allowed to touch the towels but leans forward to smell the towel then rates the towel on a smell-scale of 1 to 10, where 1 is the an extremely unpleasant smell and 10 is a very good smell. A smell rating of 8 is typically attributed to a towel that is dried in the dryer. The mean smell rating for these 20 towels is approximately normal with a mean of 8.45 and the standard deviation is 0.887. A statistician performs a test of Ho μ = 8 versus H₁ μ> 8 where is the true mean smell rating for all towels dried in the sun. This test yields a P-value of 0.0176. What conclusion would you make at the significance level a = 0.05? Because the P-value of 0.0176 < α =…

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