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Clothes dried outside smell better than those dried in a dryer because of a process called photolysis. Sunlight breaks down compounds that cause odor. A trained smeller is asked to smell a random sample of 20 towels. The smeller does not know it, but all of the 20 towels have been dried in the sun. The smeller is blindfolded and is not allowed to touch the towels but leans forward to smell the towel then rates the towel on a smell-scale of 1 to 10, where 1 is the an extremely unpleasant smell and 10 is a very good smell. A smell rating of 8 is typically attributed to a towel that is dried in the dryer. The mean smell rating for these 20 towels is approximately normal with a mean of 8.45 and the standard deviation is 0.887. A statistician performs a test of Ho μ = 8 versus H₁ μ> 8 where is the true mean smell rating for all towels dried in the sun. This test yields a P-value of 0.0176. What conclusion would you make at the significance level a = 0.05? Because the P-value of 0.0176 < α = 0.05, we reject H₂0. We have convincing evidence that the true mean smell rating for all towels dried in the sun is greater than 8, on average. Because the P-value of 0.0176 < α = 0.05, we fail to reject Ho. We do not have convincing evidence that the true mean smell rating for all towels dried in the sun is greater than 8, on average. Because the P-value of 0.0176 < α = 0.05, we reject Ho. We do not have convincing evidence that the true mean smell rating for all towels dried in the sun is greater than 8, on average. We cannot draw a conclusion because the conditions for inference are not met. Because the P-value of 0.0176 < α = 0.05, we fail to reject H0. We have convincing evidence that the true mean smell rating for all towels dried in the sun is greater than 8, on average.

Clothes dried outside smell better than those dried in a dryer because of a process called photolysis. Sunlight breaks down compounds that cause odor. A trained smeller is asked to smell a random sample of 20 towels. The smeller does not know it, but all of the 20 towels have been dried in the sun. The smeller is blindfolded and is not allowed to touch the towels but leans forward to smell the towel then rates the towel on a smell-scale of 1 to 10, where 1 is the an extremely unpleasant smell and 10 is a very good smell. A smell rating of 8 is typically attributed to a towel that is dried in the dryer. The mean smell rating for these 20 towels is approximately normal with a mean of 8.45 and the standard deviation is 0.887. A statistician performs a test of Ho μ = 8 versus H₁ μ> 8 where is the true mean smell rating for all towels dried in the sun. This test yields a P-value of 0.0176. What conclusion would you make at the significance level a = 0.05? Because the P-value of 0.0176 < α = 0.05, we reject H₂0. We have convincing evidence that the true mean smell rating for all towels dried in the sun is greater than 8, on average. Because the P-value of 0.0176 < α = 0.05, we fail to reject Ho. We do not have convincing evidence that the true mean smell rating for all towels dried in the sun is greater than 8, on average. Because the P-value of 0.0176 < α = 0.05, we reject Ho. We do not have convincing evidence that the true mean smell rating for all towels dried in the sun is greater than 8, on average. We cannot draw a conclusion because the conditions for inference are not met. Because the P-value of 0.0176 < α = 0.05, we fail to reject H0. We have convincing evidence that the true mean smell rating for all towels dried in the sun is greater than 8, on average.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Clothes dried outside smell better than those dried in a dryer because of a process called photolysis. Sunlight breaks down compounds that cause odor. A trained smeller is asked to smell a random sample of 20 towels. The smeller does not know it, but all of the 20 towels have been dried in the sun. The smeller is blindfolded and is not allowed to touch the towels but leans forward to smell the towel then rates the towel on a smell-scale of 1 to 10, where 1 is the an extremely unpleasant smell and 10 is a very good smell. A smell rating of 8 is typically attributed to a towel that is dried in the dryer. The mean smell rating for these 20 towels is approximately normal with a mean of 8.45 and the standard deviation is 0.887. A statistician performs a test of Ho μ = 8 versus H₁ μ> 8 where is the true mean smell rating for all towels dried in the sun. This test yields a P-value of 0.0176. What conclusion would you make at the significance level a = 0.05? Because the P-value of 0.0176 < α = 0.05, we reject H₂0. We have convincing evidence that the true mean smell rating for all towels dried in the sun is greater than 8, on average. Because the P-value of 0.0176 < α = 0.05, we fail to reject Ho. We do not have convincing evidence that the true mean smell rating for all towels dried in the sun is greater than 8, on average. Because the P-value of 0.0176 < α = 0.05, we reject Ho. We do not have convincing evidence that the true mean smell rating for all towels dried in the sun is greater than 8, on average. We cannot draw a conclusion because the conditions for inference are not met. Because the P-value of 0.0176 < α = 0.05, we fail to reject H0. We have convincing evidence that the true mean smell rating for all towels dried in the sun is greater than 8, on average.
Transcribed Image Text:Clothes dried outside smell better than those dried in a dryer because of a process called photolysis. Sunlight breaks down compounds that cause odor. A trained smeller is asked to smell a random sample of 20 towels. The smeller does not know it, but all of the 20 towels have been dried in the sun. The smeller is blindfolded and is not allowed to touch the towels but leans forward to smell the towel then rates the towel on a smell-scale of 1 to 10, where 1 is the an extremely unpleasant smell and 10 is a very good smell. A smell rating of 8 is typically attributed to a towel that is dried in the dryer. The mean smell rating for these 20 towels is approximately normal with a mean of 8.45 and the standard deviation is 0.887. A statistician performs a test of Ho μ = 8 versus H₁ μ> 8 where is the true mean smell rating for all towels dried in the sun. This test yields a P-value of 0.0176. What conclusion would you make at the significance level a = 0.05? Because the P-value of 0.0176 < α = 0.05, we reject H₂0. We have convincing evidence that the true mean smell rating for all towels dried in the sun is greater than 8, on average. Because the P-value of 0.0176 < α = 0.05, we fail to reject Ho. We do not have convincing evidence that the true mean smell rating for all towels dried in the sun is greater than 8, on average. Because the P-value of 0.0176 < α = 0.05, we reject Ho. We do not have convincing evidence that the true mean smell rating for all towels dried in the sun is greater than 8, on average. We cannot draw a conclusion because the conditions for inference are not met. Because the P-value of 0.0176 < α = 0.05, we fail to reject H0. We have convincing evidence that the true mean smell rating for all towels dried in the sun is greater than 8, on average.
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