The decomposition of dinitrogen pentoxide in carbon tetrachloride solution at 30 °C N2O5 2 N02 +½ 02

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**The Decomposition of Dinitrogen Pentoxide**

**Reaction Overview:**
The decomposition of dinitrogen pentoxide (N₂O₅) in carbon tetrachloride solution at 30 °C proceeds according to the following reaction:
\[ \text{N}_2\text{O}_5 \rightarrow 2 \text{NO}_2 + \frac{1}{2} \text{O}_2 \]

**Rate Law:**
This reaction is first order with respect to N₂O₅, having a rate constant (k) of \(4.10 \times 10^{-3}\) min⁻¹. 

**Problem Statement:**
If the initial concentration of N₂O₅ is 0.417 M, determine the time required (in minutes) for the concentration of N₂O₅ to decrease to \(5.25 \times 10^{-2}\) M.

**Action Required:**
- Input the calculated time in the blank provided.
- Two options for interaction:
  - Submit Answer
  - Retry Entire Group

**Additional Information:**
- The display shows there are 9 more group attempts remaining.
  
**Explanation of the Reaction Order:**
For a first-order reaction, the rate of decomposition can be expressed using the integrated first-order rate law formula:
\[ [\text{N}_2\text{O}_5] = [\text{N}_2\text{O}_5]_0 e^{-kt} \]
Where:
- \([\text{N}_2\text{O}_5]\) is the concentration of N₂O₅ at time t.
- \([\text{N}_2\text{O}_5]_0\) is the initial concentration of N₂O₅.
- \(k\) is the rate constant.
- \(t\) is the time elapsed.

This formula can be rearranged to solve for time \(t\) when the concentration at time \(t\) and the rate constant are known.

**Example Calculation:**
Given:
- Initial concentration, \([\text{N}_2\text{O}_5]_0 = 0.417\) M
- Final concentration, \([\text{N}_2\text{O}_5] = 5.25 \times 10^{-2}\) M
- Rate constant, \(k = 4.10 \times
Transcribed Image Text:**The Decomposition of Dinitrogen Pentoxide** **Reaction Overview:** The decomposition of dinitrogen pentoxide (N₂O₅) in carbon tetrachloride solution at 30 °C proceeds according to the following reaction: \[ \text{N}_2\text{O}_5 \rightarrow 2 \text{NO}_2 + \frac{1}{2} \text{O}_2 \] **Rate Law:** This reaction is first order with respect to N₂O₅, having a rate constant (k) of \(4.10 \times 10^{-3}\) min⁻¹. **Problem Statement:** If the initial concentration of N₂O₅ is 0.417 M, determine the time required (in minutes) for the concentration of N₂O₅ to decrease to \(5.25 \times 10^{-2}\) M. **Action Required:** - Input the calculated time in the blank provided. - Two options for interaction: - Submit Answer - Retry Entire Group **Additional Information:** - The display shows there are 9 more group attempts remaining. **Explanation of the Reaction Order:** For a first-order reaction, the rate of decomposition can be expressed using the integrated first-order rate law formula: \[ [\text{N}_2\text{O}_5] = [\text{N}_2\text{O}_5]_0 e^{-kt} \] Where: - \([\text{N}_2\text{O}_5]\) is the concentration of N₂O₅ at time t. - \([\text{N}_2\text{O}_5]_0\) is the initial concentration of N₂O₅. - \(k\) is the rate constant. - \(t\) is the time elapsed. This formula can be rearranged to solve for time \(t\) when the concentration at time \(t\) and the rate constant are known. **Example Calculation:** Given: - Initial concentration, \([\text{N}_2\text{O}_5]_0 = 0.417\) M - Final concentration, \([\text{N}_2\text{O}_5] = 5.25 \times 10^{-2}\) M - Rate constant, \(k = 4.10 \times
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