The data table below shows the number of 100 cars sold for a specific brand. Researchers want to determine if there is a preference, the null hypothesis is that there is none. Model Ford Toyota Dodge BMW #Sold 20 30 30 20 Calculate the expected frequencies? Calculate the test statistic (Chi-Squared)? Using the critical value and the area of the upper tail (df=3), should we

The data table below shows the number of 100 cars sold for a specific brand. Researchers want to determine if there is a preference, the null hypothesis is that there is none. Model Ford Toyota Dodge BMW #Sold 20 30 30 20 Calculate the expected frequencies? Calculate the test statistic (Chi-Squared)? Using the critical value and the area of the upper tail (df=3), should we

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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The time necessary to complete the technical interview for the Google intership is normally distributed with a mean of sixty-three minutes, and a standard deviation of twelve minutes. Let the random variable X represent the number of minutes a randomly chosen student takes to complete the assessment. If a sample of three dozen students is taken, what is the standard deviation of the sample mean σX¯ and what is the probability that the sample mean would be 59 minutes or fewer?
A data set includes data from 500 random tornadoes. The display from technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.7 miles. Use a 0.05 significance level. Use the display to identify the null and alternative hypotheses, test statistic, and P-value. State the final conclusion that addresses the original claim.
A Data analytics professor wants to know whether level of college education influences the grade earned by students in his course. Last semester, 400 students completed his class: 150 freshmen, 100 sophomores, 100 juniors, and 50 seniors. At end of the semester, 80 students earned an A, 148 earned a B, and 172 earned a C. The distribution of grades is shown in the following table. Do a chi-square test at alpha=0.05. What is the null hypothesis for this test? A. The letter grades of the students are significantly different. B. The letter grades of the students are dependent of the level of college education. C. The letter grades of the students are identical. D. The letter grades of the students are independent of the level of college education.
Women are recommended to consume 1790 calories per day. You suspect that the average calorie intake is larger for women at your college. The data for the 11 women who participated in the study is shown below: 2035, 2079, 1842, 1923, 1701, 1889, 1691, 1731, 1730, 2006, 1954 Assuming that the distribution is normal, what can be concluded at the αα = 0.01 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer = > < ≠ H1:H1: ? μ p Select an answer ≠ < = > The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer accept fail to reject reject the null hypothesis. Thus, the final conclusion is that ... The data suggest that the population mean calorie…
Do men talk less than women? The table shows results from a study of the words spoken in a day by men and women. Assume that the two samples are randomly selected, independent, the population standard deviations are not know and not considered equal. At the 0.05 significance level, test the claim that the mean number of words spoken by men is less than the mean number of words spoken by women. Men Women n1 = 212 n2 = 218 xˉx̄1 = 15706.4 words xˉx̄2 = 15683.2 words s1 = 1595.44 words s2 = 1597.54 words What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.)H0: Select an answer μ₁ μ σ₁² x̄₂ p x̄₁ s₁² p̂₁ μ(men) p₂ p₁ μ₂ ? ≤ > ≥ = ≠ < Select an answer μ₁ p₁ μ₂ x̄₂ σ₁² p̂₁ μ s₁² μ(women) p x̄₁ p₂ H1: Select an answer p̂₂ p s₂² σ₂² μ(men) μ μ₂ x̄₂ x̄₁ p₂ μ₁ p₁ ? < > = ≠ ≥ ≤ Select an answer μ₂ μ p₂ s₁² p₁ x̄₁ σ₁² p̂₁ p μ₁ x̄₂ μ(women) Original Claim = Select an answer H₁ H₀ df = Based on the hypotheses, find the…
A random sample of 23 bags of apples (marked as 10 pounds each) received by a large grocery chain tested out as having a mean of 9.2 pounds with a variance of 2.56 pounds. Test whether the true mean of all bags is under 10 pounds. Set up hypotheses. Perform the appropriate test by showing your formula. Interpret the results using a Type I (alpha) error of .05. Also provide the p value here. Also construct a 95% confidence interval around your sample mean (X bar) that should contain the true mean (mu). Also interpret this interval.
A data set includes data from student evaluations of courses. The summary statistics are n= 88, x= 4.09, s 0.66. Use a 0.05 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? O A. Ho: H=4.25 H: p4.25 Determine the test statistic. (Round to two decimal places as needed.) Determine the P-value. (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. Ho. There is evidence to conclude that the mean of the population of student course evaluations is equal to 4.25 correct.
Using traditional methods it takes 107 hours to receive an advanced flying license. A new training technique using Computer Aided Instruction (CAI) has been proposed. A researcher used the technique on 150 students and observed that they had a mean of 106 hours. Assume the population standard deviation is known to be 5 . Is there evidence at the 0.01 level that the technique performs differently than the traditional method? Step 1 of 6 : State the null and alternative hypotheses.