Do rats take less time on average than hamsters to travel through a maze? The table below shows the times in seconds that the rats and hamsters took. Rats: 21, 28, 38, 34, 25, 42, 35, 32 Hamsters: 48, 43, 31, 39, 49, 27, 40, 40 Assume that both populations follow a normal distribution. What can be concluded at the αα = 0.01 level of significance level of significance? 1. For this study, we should use ?Select an answer t-test for the difference between two dependent population means? t-test for a population mean? z-test for a population proportion ? t-test for the difference between two independent population means? or z-test for the difference between two population proportions? 2. The null and alternative hypotheses would be: H0: Select an answer μ1 or p1 Select an answer > ≠ < = Select an answer p2 or μ2 (please enter a decimal) H1:Select an answer μ1 or p1 Select an answer ≠ > < = Select an answer μ2 or p2 3. The test statistic: z or t =_________ (please show your answer to 3 decimal places.) 4. The p-value =_______ (Please show your answer to 4 decimal places.) 5. The p-value is ? ≤ or > 6. Based on this, we should? Select an answer fail to reject? accept? or reject? the null hypothesis. 6.Thus, the final conclusion is that ... The results are statistically insignificant at αα = 0.01, so there is insufficient evidence to conclude that the population mean time to complete the maze for rats is less than the population mean time to complete the maze for hamsters. The results are statistically insignificant at αα = 0.01, so there is statistically significant evidence to conclude that the population mean time to complete the maze for rats is equal to the population mean time to complete the maze for hamsters. The results are statistically significant at αα = 0.01, so there is sufficient evidence to conclude that the mean time to complete the maze for the eight rats is less than the mean time to complete the maze for the eight hamsters. The results are statistically significant at αα = 0.01, so there is sufficient evidence to conclude that the population mean time to complete the maze for rats is less than the population mean time to complete the maze for hamsters. 7. Interpret the p-value in the context of the study. There is a 2.56% chance of a Type I error. There is a 2.56% chance that the mean time to complete the maze for the 8 rats is at least 7.8 seconds less than the mean time to complete the maze for the 8 hamsters. If the sample mean time to complete the maze for the 8 rats is the same as the sample mean time to complete the maze for the 8 hamsters and if another 8 rats and 8 hamsters are observed then there would be a 2.56% chance of concluding that the mean time to complete the maze for the 8 rats is at least 7.8 seconds less than the mean time to complete the maze for the 8 hamsters. If the population mean time to complete the maze for rats is the same as the population mean time to complete the maze for hamsters and if another 8 rats and 8 hamsters are observed then there would be a 2.56% chance that the mean time to complete the maze for the 8 rats would be at least 7.8 seconds less than the mean time to complete the maze for the 8 hamsters. 8. Interpret the level of significance in the context of the study. If the population mean time to complete the maze for rats is the same as the population mean time to complete the maze for hamsters and if another 8 rats and 8 hamsters are observed, then there would be a 1% chance that we would end up falsely concluding that the sample mean time to complete the maze for these 8 rats and 8 hamsters differ from each other. There is a 1% chance that the rat will eat the hamster. There is a 1% chance that the population mean time to complete the maze for rats and hamsters is the same. If the population mean time to complete the maze for rats is the same as the population mean time to complete the maze for hamsters and if another 8 rats and 8 hamsters are observed then there would be a 1% chance that we would end up falsely concluding that the population mean time to complete the maze for rats is less than the population mean time to complete the maze for hamsters

Do rats take less time on average than hamsters to travel through a maze? The table below shows the times in seconds that the rats and hamsters took. Rats: 21, 28, 38, 34, 25, 42, 35, 32 Hamsters: 48, 43, 31, 39, 49, 27, 40, 40 Assume that both populations follow a normal distribution. What can be concluded at the αα = 0.01 level of significance level of significance? 1. For this study, we should use ?Select an answer t-test for the difference between two dependent population means? t-test for a population mean? z-test for a population proportion ? t-test for the difference between two independent population means? or z-test for the difference between two population proportions? 2. The null and alternative hypotheses would be: H0: Select an answer μ1 or p1 Select an answer > ≠ < = Select an answer p2 or μ2 (please enter a decimal) H1:Select an answer μ1 or p1 Select an answer ≠ > < = Select an answer μ2 or p2 3. The test statistic: z or t =___ (please show your answer to 3 decimal places.) 4. The p-value =_ (Please show your answer to 4 decimal places.) 5. The p-value is ? ≤ or > 6. Based on this, we should? Select an answer fail to reject? accept? or reject? the null hypothesis. 6.Thus, the final conclusion is that ... The results are statistically insignificant at αα = 0.01, so there is insufficient evidence to conclude that the population mean time to complete the maze for rats is less than the population mean time to complete the maze for hamsters. The results are statistically insignificant at αα = 0.01, so there is statistically significant evidence to conclude that the population mean time to complete the maze for rats is equal to the population mean time to complete the maze for hamsters. The results are statistically significant at αα = 0.01, so there is sufficient evidence to conclude that the mean time to complete the maze for the eight rats is less than the mean time to complete the maze for the eight hamsters. The results are statistically significant at αα = 0.01, so there is sufficient evidence to conclude that the population mean time to complete the maze for rats is less than the population mean time to complete the maze for hamsters. 7. Interpret the p-value in the context of the study. There is a 2.56% chance of a Type I error. There is a 2.56% chance that the mean time to complete the maze for the 8 rats is at least 7.8 seconds less than the mean time to complete the maze for the 8 hamsters. If the sample mean time to complete the maze for the 8 rats is the same as the sample mean time to complete the maze for the 8 hamsters and if another 8 rats and 8 hamsters are observed then there would be a 2.56% chance of concluding that the mean time to complete the maze for the 8 rats is at least 7.8 seconds less than the mean time to complete the maze for the 8 hamsters. If the population mean time to complete the maze for rats is the same as the population mean time to complete the maze for hamsters and if another 8 rats and 8 hamsters are observed then there would be a 2.56% chance that the mean time to complete the maze for the 8 rats would be at least 7.8 seconds less than the mean time to complete the maze for the 8 hamsters. 8. Interpret the level of significance in the context of the study. If the population mean time to complete the maze for rats is the same as the population mean time to complete the maze for hamsters and if another 8 rats and 8 hamsters are observed, then there would be a 1% chance that we would end up falsely concluding that the sample mean time to complete the maze for these 8 rats and 8 hamsters differ from each other. There is a 1% chance that the rat will eat the hamster. There is a 1% chance that the population mean time to complete the maze for rats and hamsters is the same. If the population mean time to complete the maze for rats is the same as the population mean time to complete the maze for hamsters and if another 8 rats and 8 hamsters are observed then there would be a 1% chance that we would end up falsely concluding that the population mean time to complete the maze for rats is less than the population mean time to complete the maze for hamsters

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Topic Video

Question

Do rats take less time on average than hamsters to travel through a maze? The table below shows the times in seconds that the rats and hamsters took.

Rats: 21, 28, 38, 34, 25, 42, 35, 32

Hamsters: 48, 43, 31, 39, 49, 27, 40, 40

Assume that both populations follow a normal distribution. What can be concluded at the αα = 0.01 level of significance level of significance?

1. For this study, we should use ?Select an answer t-test for the difference between two dependent population means? t-test for a population mean? z-test for a population proportion ? t-test for the difference between two independent population means? or z-test for the difference between two population proportions?

2. The null and alternative hypotheses would be:

H0: Select an answer μ1 or p1 Select an answer > ≠ < = Select an answer p2 or μ2 (please enter a decimal)

H1:Select an answer μ1 or p1 Select an answer ≠ > < = Select an answer μ2 or p2

3. The test statistic: z or t =_________ (please show your answer to 3 decimal places.)

4. The p-value =_______ (Please show your answer to 4 decimal places.)

5. The p-value is ? ≤ or >

6. Based on this, we should? Select an answer fail to reject? accept? or reject? the null hypothesis.

6.Thus, the final conclusion is that ...

The results are statistically insignificant at αα = 0.01, so there is insufficient evidence to conclude that the population mean time to complete the maze for rats is less than the population mean time to complete the maze for hamsters.
The results are statistically insignificant at αα = 0.01, so there is statistically significant evidence to conclude that the population mean time to complete the maze for rats is equal to the population mean time to complete the maze for hamsters.
The results are statistically significant at αα = 0.01, so there is sufficient evidence to conclude that the mean time to complete the maze for the eight rats is less than the mean time to complete the maze for the eight hamsters.
The results are statistically significant at αα = 0.01, so there is sufficient evidence to conclude that the population mean time to complete the maze for rats is less than the population mean time to complete the maze for hamsters.

7. Interpret the p-value in the context of the study.

There is a 2.56% chance of a Type I error.
There is a 2.56% chance that the mean time to complete the maze for the 8 rats is at least 7.8 seconds less than the mean time to complete the maze for the 8 hamsters.
If the sample mean time to complete the maze for the 8 rats is the same as the sample mean time to complete the maze for the 8 hamsters and if another 8 rats and 8 hamsters are observed then there would be a 2.56% chance of concluding that the mean time to complete the maze for the 8 rats is at least 7.8 seconds less than the mean time to complete the maze for the 8 hamsters.
If the population mean time to complete the maze for rats is the same as the population mean time to complete the maze for hamsters and if another 8 rats and 8 hamsters are observed then there would be a 2.56% chance that the mean time to complete the maze for the 8 rats would be at least 7.8 seconds less than the mean time to complete the maze for the 8 hamsters.

8. Interpret the level of significance in the context of the study.

If the population mean time to complete the maze for rats is the same as the population mean time to complete the maze for hamsters and if another 8 rats and 8 hamsters are observed, then there would be a 1% chance that we would end up falsely concluding that the sample mean time to complete the maze for these 8 rats and 8 hamsters differ from each other.
There is a 1% chance that the rat will eat the hamster.
There is a 1% chance that the population mean time to complete the maze for rats and hamsters is the same.
If the population mean time to complete the maze for rats is the same as the population mean time to complete the maze for hamsters and if another 8 rats and 8 hamsters are observed then there would be a 1% chance that we would end up falsely concluding that the population mean time to complete the maze for rats is less than the population mean time to complete the maze for hamsters

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 5 steps with 5 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Hypothesis Tests and Confidence Intervals for Means$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.