The data in the table were collected at 580 K for the reaction 2 HI(g) → H₂(g) + L₂(g) Time (s) [HI] (mol.L-¹) 0 1.00 1000. 0.11 2000. 0.061 3000. 0.041 4000. 0.031 From the graph, determine the rate constant, k, for the loss of HI. k= TOOLS x10 Using a graphing calculator or software, plot the data in an appropriate fashion to determine the order of the reaction: O 0 O 1 2 Determine the units of the rate constant. mol-L-¹.1 L.mol-¹.s-¹
The data in the table were collected at 580 K for the reaction 2 HI(g) → H₂(g) + L₂(g) Time (s) [HI] (mol.L-¹) 0 1.00 1000. 0.11 2000. 0.061 3000. 0.041 4000. 0.031 From the graph, determine the rate constant, k, for the loss of HI. k= TOOLS x10 Using a graphing calculator or software, plot the data in an appropriate fashion to determine the order of the reaction: O 0 O 1 2 Determine the units of the rate constant. mol-L-¹.1 L.mol-¹.s-¹
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Kinetics - Determining the Order of Reaction and Rate Constant Calculation**
This educational segment aims to elucidate the method of determining the order of a chemical reaction and its corresponding rate constant, \( k \), based on experimental data.
### Reaction Data
The data was collected at 580 K for the reaction:
\[ 2 \, \text{HI(g)} \rightarrow \text{H}_2(g) + \text{I}_2(g) \]
**Table of Data:**
| Time (s) | [HI] (mol·L\(^{-1}\)) |
|----------|-----------------------|
| 0 | 1.00 |
| 1000 | 0.11 |
| 2000 | 0.061 |
| 3000 | 0.041 |
| 4000 | 0.031 |
### Data Analysis
1. **Plotting the Data:**
Using a graphing calculator or software, plot the concentration of HI against time to determine the reaction order.
2. **Determination of Reaction Order:**
Plot the data in an appropriate graph:
- Zero-order: [HI] vs. Time
- First-order: ln[HI] vs. Time
- Second-order: \( \frac{1}{[\text{HI}]} \) vs. Time
Based on the provided question, it is suggested that the reaction order is 2. Therefore, a second-order reaction graph \( \frac{1}{[\text{HI}]} \) vs. Time should be linear.
3. **Graph Interpretation:**
Upon plotting, if \( \frac{1}{[\text{HI}]} \) vs. Time yields a straight line, it confirms the reaction is second-order.
### Rate Constant Calculation
From the graph, determine the rate constant, \( k \), for the loss of HI.
\[ k = \text{(Slope of the line in the second-order plot)} \]
**Example Calculation:**
Assuming the line fits the second-order reaction model perfectly, the slope \( k \) can be determined directly from the graph.
### Units of Rate Constant
For a second-order reaction, the units of the rate constant \( k \) are \( \text{L·mol}^{-1}\text{s}^{-1} \).
### Conclusion
By plotting the concentration](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe32cdaa3-49b3-4b1d-929d-b728cde894e8%2F34be8592-9cc3-479b-875c-8b2379c2b2e7%2Fpwgzk9i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:---
**Kinetics - Determining the Order of Reaction and Rate Constant Calculation**
This educational segment aims to elucidate the method of determining the order of a chemical reaction and its corresponding rate constant, \( k \), based on experimental data.
### Reaction Data
The data was collected at 580 K for the reaction:
\[ 2 \, \text{HI(g)} \rightarrow \text{H}_2(g) + \text{I}_2(g) \]
**Table of Data:**
| Time (s) | [HI] (mol·L\(^{-1}\)) |
|----------|-----------------------|
| 0 | 1.00 |
| 1000 | 0.11 |
| 2000 | 0.061 |
| 3000 | 0.041 |
| 4000 | 0.031 |
### Data Analysis
1. **Plotting the Data:**
Using a graphing calculator or software, plot the concentration of HI against time to determine the reaction order.
2. **Determination of Reaction Order:**
Plot the data in an appropriate graph:
- Zero-order: [HI] vs. Time
- First-order: ln[HI] vs. Time
- Second-order: \( \frac{1}{[\text{HI}]} \) vs. Time
Based on the provided question, it is suggested that the reaction order is 2. Therefore, a second-order reaction graph \( \frac{1}{[\text{HI}]} \) vs. Time should be linear.
3. **Graph Interpretation:**
Upon plotting, if \( \frac{1}{[\text{HI}]} \) vs. Time yields a straight line, it confirms the reaction is second-order.
### Rate Constant Calculation
From the graph, determine the rate constant, \( k \), for the loss of HI.
\[ k = \text{(Slope of the line in the second-order plot)} \]
**Example Calculation:**
Assuming the line fits the second-order reaction model perfectly, the slope \( k \) can be determined directly from the graph.
### Units of Rate Constant
For a second-order reaction, the units of the rate constant \( k \) are \( \text{L·mol}^{-1}\text{s}^{-1} \).
### Conclusion
By plotting the concentration
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