The daily total cost (y) in dollars for production of (x) items follows the SLR model: Y = 125 + 0.12x + ε with σ = 10 a) Find the expected total cost corresponding to 200 items produced. b) What is the probability the total cost is less than $160 for 200 items produced?

The daily total cost (y) in dollars for production of (x) items follows the SLR model: Y = 125 + 0.12x + ε with σ = 10 a) Find the expected total cost corresponding to 200 items produced. b) What is the probability the total cost is less than $160 for 200 items produced?

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Total plasma volume is important in determining the required plasma component in blood replacement therapy for a person undergoing surgery. Plasma volume is influenced by the overall health and physical activity of an individual. Suppose that a random sample of 43 male firefighters are tested and that they have a plasma volume sample mean of x = 37.5 ml/kg (milliliters plasma per kilogram body weight). Assume that σ = 7.50 ml/kg for the distribution of blood plasma. (a) Find a 99% confidence interval for the population mean blood plasma volume in male firefighters. What is the margin of error? (Round your answers to two decimal places.) lower limit 1 upper limit 2 margin of error 3 (b) What conditions are necessary for your calculations? (Select all that apply.) n is large the distribution of weights is normal σ is known the distribution of weights is uniform σ is unknown (c) Interpret your results in the context of this problem. 1% of the intervals created using…
A sample obtained from a population with σ = 12 has a standard error of σx̅ = 2 points. How many scores are in the sample?
Write the following distributions in the form of the exponential form: (i) Poisson P(0); (ii) Geometric G(0); (iii) Gamma I'(a, B).
A technician discovered that the cumulative distribution function (CDF) of the lifespan of bulb in years is given by f(y) = -10 ye 10 100 0
10. A sample of high-capacity resistors is tested until failure and the results fitted to a Weibull probability model. Based on these tests, the reliability function of a resis- tor is estimated to be -0.0013 rl.83 R(1) = e' a. What is the failure rate function for these resistors? b. Is this resistor more likely to fail as it ages? c. What is the probability that a resistor will function for more than 30 hours with- out failure? d. Suppose that a resistor has been operating for 50 hours. What is the probability that it fails in the 5 1st hour? [Use the results of part (a) for your calculations.]
Estimate ff e+y“ dA with R = [0, 3] × [0, 3] using m = n = 2 and midpoints as your R sample points.
Suppose you simulate the price path of stock HHF using a geometric Brownian motion model with µ = 0.1, o = 0.2, and time step At = 1/52 (weekly). Let St be the price of the stock at time t. If So = 100, and the first simulated (randomly selected) standard normal variable is e = -0.591, what is the simulated return over the next week? (a) -0.061 (b) -0.015 (c) 0.061 (d) -0.093
The lifetime, in hours, of a head gasket of a cylinder in a car engine is distributed as lognormal with parameters a = 10.328 and ß = 1.575. (a) Determine the mean. 105694.96120 (b) Determine the standard deviation. 349732.63296 (c) Find the probability that the lifetime of the head gasket is between 5748 and 8435 hours.
In the daily production of a certain kind of rope, the number of defects per foot given by Y is assumed to have a Poisson distribution with mean λ = 3. The profit per foot when the rope is sold is given by X, where X = 60 - 4Y - y². Find the expected profit per foot. $ per foot
4) What number of drones N makes your second-morning observations as likely as possible?5) Assuming again that the probability that N = n is proportional to the probability of observing this specificdata on the second day, find again the smallest nmax so that P (N ≤ nmax) = 0.95.