10. A sample of high-capacity resistors is tested until failure and the results fitted to aWeibull probability model. Based on these tests, the reliability function of a resis-tor is estimated to be-0.0013 rl.83R(1) = e'a. What is the failure rate function for these resistors?b. Is this resistor more likely to fail as it ages?c. What is the probability that a resistor will function for more than 30 hours with-out failure?d. Suppose that a resistor has been operating for 50 hours. What is the probabilitythat it fails in the 5 1st hour? [Use the results of part (a) for your calculations.]

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Answered: 10. A sample of high-capacity resistors…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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arn.squ.edu.om/mod/quiz/attempt.php?attempt=1766808&cmid=8751228&page=D21 SYSTEM (ACADEMIC) s Statistics 1 || Spring21 Time left 0: Suppose a company produces lightbulbs with a mean lifetime of 1000 hours and a standard deviation of 50 hours. So, the z-score for a particular lightbulb that lasts for only 700 hours is a. 300 b. 6
The desired percentage of Sio, in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5 for a particular production facility, 16 independently obtained samples are analyzed. Suppose that the percentage of Sio, in a sample is normally distributed with o = 0.32 and that x = 5.23. (Use a = 0.05.) (a) Does this indicate conclusively that the true average percentage differs from 5.5? State the appropriate null and alternative hypotheses. Ho: u = 5.5 Hg: µ 2 5.5 Ho: H = 5.5 HaiH 5.5 = Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Do not reject the null hypothesis. There is not sufficient evidence to conclude that the true average percentage differs from the desired percentage. O Reject the null hypothesis. There is sufficient evidence to conclude that the true average percentage differs from the…
The distribution of life spans is approximately normal and u=40, how large a sample is required in order that the probability of committing a type II error be 0.1 when the true mean is 35.9 months? Assume that o = 5.8 months.
Q1: Lifetimes of a certain component are lognormally distributed with parameters u = 1 day and o = 0.5 days. Find the mean lifetime of these components. 1-Find the standard deviation of the lifetimes. 2-Find CDF 3- Find reliability at t= 4 day
A researcher claims that the average wind speed in a certain city is 8 miles per hour. A sample of 32 days has an average wind speed of 8.2 miles per hour. The standard deviation of the population is 0.6 mile per hour. At 0.05, is there enough evidence to reject the claim? STEP 2. The critical value (s) is/are: z1 = z2 =
The desired percentage of SiO₂ in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5 for a particular production facility, 16 independently obtained samples are analyzed. Suppose that the percentage of SiO₂ in a sample is normally distributed with = 0.32 and that x = 5.23. (Use a = 0.05.) (a) Does this indicate conclusively that the true average percentage differs from 5.5? State the appropriate null and alternative hypotheses. O Ho: μ = 5.5 H₂:μ> 5.5 O Ho: μ = 5.5 H₂: μ = 5.5 ⒸHO: μ = 5.5 H₂:μ ≥ 5.5 O Ho: μ = 5.5 H₂: μ< 5.5 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) Z = P-value = State the conclusion in the problem context. O Do not reject the null hypothesis. There is not sufficient evidence to conclude that the true verage percentage differs from the desired percentage. O Reject the null hypothesis. There is not sufficient evidence to…
A company claims that the mean monthly residential electricity consumption in a certain region is more than 860 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 69 residential customers has a mean monthly consumption of 880 kWh. Assume the population standard deviation is 126 kWh. At α=0.01, can you support the claim? Complete parts (a) through (e). Also find the critical values.
A company claims that the mean monthly residential electricity consumption in a certain region is more than 860 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 66 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 123 kWh. At a = 0.10, can you support the claim? Complete parts (a) through (e). B. The critical value is 1.28 Identify the rejection region(s). Select the correct choice below. O A. The rejection regions are z 1.28 OB. The rejection region is z > 1.28 OC. The rejection region is z< 1.28. (c) Find the standardized test statistic. Use technology. The standardized test statistic is z = (Round to two decimal places as needed.)
Consider the problem of diagnosing a rare disease. Let’s say the occurrence of thisdisease is one in a thousand i.e. P(D = +) = 0.001. There is a test T which correctlyidentifies the disease 99.9% of the time, i.e. P(T = +|D = +) = 0.999. However, italso has a false positive rate of 0.02, i.e. P(T = +|D = −) = 0.02 i. If a random person from the population is tested, what is the probability they willreceive a positive test, i.e. P(T = +)? ii. Given that the test is positive, what is the probability that the person has the disease,i.e. P(D = +|T = +)?
Please solve
PLEASE ANSWER Z, P-VALUE TY!

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