The image depicts a circuit with five resistors arranged in a combination of series and parallel connections. The current, \(i = 36 \, \text{mA}\), flows through the system. The resistor values are given as follows: \(R_1 = 5 \, \Omega\), \(R_2 = 7 \, \Omega\), \(R_3 = 2 \, \Omega\), \(R_4 = 8 \, \Omega\), and \(R_5 = 6 \, \Omega\). Kirchhoff's rules are used to determine the current in each resistor.The circuit diagram shows the resistors positioned with:- \(R_1\) and \(R_2\) on the left branch.- \(R_3\) and \(R_4\) on the right branch.- \(R_5\) bridging the middle sections of the branches.The calculated currents are:- \(I_1\) through \(R_1\): \(18.445 \, \text{mA}\)- \(I_2\) through \(R_2\): \(19.555 \, \text{mA}\)- \(I_3\) through \(R_3\): \(-11.034 \, \text{mA}\) (indicating opposite direction)- \(I_4\) through \(R_4\): \(47.034 \, \text{mA}\)- \(I_5\) through \(R_5\): \(27.479 \, \text{mA}\)The direction of the current through \(R_5\) is noted as "UP."

Answered: Image /qna-images/answer/3eb49cb8-c820-471b-b747-c36c0604850a.jpg

The current i = 36 mA is passing through a system of five resistors connected as shown in the circuit below. Find the magnitude of the current in each resistor if R, = 5 0, R2 = 7 0, R3 = 2 0, R4 = 8 0, and Rg = 6 0. Use Kirchhoff's rules to solve for the currents. R, R3 ww R5 ww i R2 R4 The current through R, i, =| 18.445 X Units mA The current through R2, iz = 19.555 X Units mA The current through R3, iz =-11.034 X Units mA The current through R4, 14 =| 47.034 X Units mA The current through Rg, ig =| 27.479 X Units mA The direction of the current through Rg is UP

The current i = 36 mA is passing through a system of five resistors connected as shown in the circuit below. Find the magnitude of the current in each resistor if R, = 5 0, R2 = 7 0, R3 = 2 0, R4 = 8 0, and Rg = 6 0. Use Kirchhoff's rules to solve for the currents. R, R3 ww R5 ww i R2 R4 The current through R, i, =| 18.445 X Units mA The current through R2, iz = 19.555 X Units mA The current through R3, iz =-11.034 X Units mA The current through R4, 14 =| 47.034 X Units mA The current through Rg, ig =| 27.479 X Units mA The direction of the current through Rg is UP

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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