In Step 3, was the potential at the high side of D2, 'pulled' higher or lower, relative to ground, by the jumper wire? Lower. This is a pull-down connection. The potential was not pulled higher or lower, because it remained unchanged. Higher. This is a pull-up connection. The potential was not pulled, it was pushed. I did not read the title of this lab assignment.

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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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In step 3, was the potential at the high side of D2, ‘pulled’ higher or lower, relative to ground, by the jumper wires
In Step 3, was the potential at the
high side of D2, 'pulled' higher or
lower, relative to ground, by the
jumper wire?
Lower. This is a pull-down connection.
The potential was not pulled higher or lower,
because it remained unchanged.
Higher. This is a pull-up connection.
The potential was not pulled, it was pushed. I
did not read the title of this lab assignment.
Transcribed Image Text:In Step 3, was the potential at the high side of D2, 'pulled' higher or lower, relative to ground, by the jumper wire? Lower. This is a pull-down connection. The potential was not pulled higher or lower, because it remained unchanged. Higher. This is a pull-up connection. The potential was not pulled, it was pushed. I did not read the title of this lab assignment.
STEP 3
Add a jumper wire to the circuit, in parallel
with D2, as illustrated in this schematic:
D1
R1
D2
Red
330 Q
Blue
PSB
5 V
You will know it is connected correctly
because D2 is shorted and goes out, causing
D1 to become brighter.
What will the voltage be across D2 now
that it has been shorted?
If there is no potential difference across
D2, then it makes sense that no current
will flow through it.
• With the jumper connecting the high side
of D2 directly to the breadboard ground
rail, what will be the new potential of tha
iunction point, relative to ground?
Transcribed Image Text:STEP 3 Add a jumper wire to the circuit, in parallel with D2, as illustrated in this schematic: D1 R1 D2 Red 330 Q Blue PSB 5 V You will know it is connected correctly because D2 is shorted and goes out, causing D1 to become brighter. What will the voltage be across D2 now that it has been shorted? If there is no potential difference across D2, then it makes sense that no current will flow through it. • With the jumper connecting the high side of D2 directly to the breadboard ground rail, what will be the new potential of tha iunction point, relative to ground?
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