The cross section of a bearing block is shown in the figure by the shaded area. Calculate the moment of inertia of the section about its base a-a. Assume b = 15 in., h = 6 in., r = 4 in, R = 6 in. a Answer: la-a = i b R in.4 h ---α
The cross section of a bearing block is shown in the figure by the shaded area. Calculate the moment of inertia of the section about its base a-a. Assume b = 15 in., h = 6 in., r = 4 in, R = 6 in. a Answer: la-a = i b R in.4 h ---α
Chapter2: Loads On Structures
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
Transcribed Image Text:## Moment of Inertia Calculation for Cross Section of Bearing Block
### Problem Statement:
The cross section of a bearing block is shown in the figure by the shaded area. Calculate the moment of inertia of the section about its base \(a \text{-} a\).
### Given:
- \( b = 15 \text{ in.} \)
- \( h = 6 \text{ in.} \)
- \( r = 4 \text{ in.} \)
- \( R = 6 \text{ in.} \)
### Diagram Explanation:
The diagram consists of a semi-circular area on top of a rectangular area. The rectangle has:
- A base \( b \) which is 15 inches long.
- A height \( h \) which is 6 inches.
The semicircle on top of the rectangle has:
- An outer radius \( R \) which is 6 inches.
- An inner cut-out semicircle with a radius \( r \) which is 4 inches.
Together, these shapes form the full cross-sectional area of the bearing block referred to as the shaded region.
### Calculation:
To find the moment of inertia \( I_{a \text{-} a} \) about the base \( a \text{-} a \), appropriate formulas and geometric considerations will be applied.
Answer: \( I_{a \text{-} a} = \boxed{\text{ }} \text{in.}^4 \)
Note: The actual numerical answer will involve computation based on the standard formulas for the moment of inertia of composite areas.
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