The concept of a weak solution of a boundary value problem plays an important role in some numerical solutions including the finite element method. The idea of a "weak solution" can be a rather weak notion. The following problem was presented in lecture 3 of week 8. It is generally not solvable in closed form. 00 on 0
The concept of a weak solution of a boundary value problem plays an important role in some numerical solutions including the finite element method. The idea of a "weak solution" can be a rather weak notion. The following problem was presented in lecture 3 of week 8. It is generally not solvable in closed form. 00 on 0
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Before posting to the discussion board, complete the following:
The concept of a weak solution of a boundary value problem plays an important role in some numerical
solutions including the finite element method. The idea of a "weak solution" can be a rather weak notion.
The following problem was presented in lecture 3 of week 8. It is generally not solvable in closed form.
0<x<1, c(x) >0 on 0<x<1
-u"(x)+c(x)u(x)=f(x),
u(0)=0, u(1)=0
The weak form of this BVP was given as
where
a(u, v) = f(v), for all v EV
a(u, v) = f'(u'v' + cuv)dx, for all u,veV, (v)=f(x)v(x) dx, for all ve V
Post a response to the following discussion questions.
What value does the weak formulation offer?
What is the possible shortcoming of the weak formulation?
Does one arrive at a minimization problem by substituting v=du, the variation in u, ; i.e.. can one arrive at
an integral
such that yields the original equation?
1
V = [ f(u,u',x) dx
v
0"
Transcribed Image Text:DISCUSSION
Before posting to the discussion board, complete the following:
The concept of a weak solution of a boundary value problem plays an important role in some numerical
solutions including the finite element method. The idea of a "weak solution" can be a rather weak notion.
The following problem was presented in lecture 3 of week 8. It is generally not solvable in closed form.
0<x<1, c(x) >0 on 0<x<1
-u"(x)+c(x)u(x)=f(x),
u(0)=0, u(1)=0
The weak form of this BVP was given as
where
a(u, v) = f(v), for all v EV
a(u, v) = f'(u'v' + cuv)dx, for all u,veV, (v)=f(x)v(x) dx, for all ve V
Post a response to the following discussion questions.
What value does the weak formulation offer?
What is the possible shortcoming of the weak formulation?
Does one arrive at a minimization problem by substituting v=du, the variation in u, ; i.e.. can one arrive at
an integral
such that yields the original equation?
1
V = [ f(u,u',x) dx
v
0
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