The compound HBr can be decomposed to form H2 and Br2. This can be represented at the atomic level by a chemical equation: 2HB H2 + Br2 According to the law of conservation of mass, if 31.7 grams of HBr decomposes and 0.4 grams of Hz is formed, how many grams of Br2 must simultaneously be formed? | grams Br2

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### Decomposition of Hydrobromic Acid (HBr)

The compound HBr (hydrobromic acid) can be decomposed to form hydrogen gas (H₂) and bromine gas (Br₂). This chemical reaction can be represented at the atomic level by the equation:

\[ \mathbf{2HBr \rightarrow H_2 + Br_2} \]

According to the law of conservation of mass, the mass of the reactants must equal the mass of the products. Given the scenario:

- **Given Data:**
  - 31.7 grams of HBr decomposes.
  - 0.4 grams of H₂ is formed.

- **Question:**
  - How many grams of Br₂ must simultaneously be formed?

**Solution:**

To determine the mass of Br₂ formed, consider the mass conservation principle:

\[ \text{Mass of } HBr = \text{Mass of } H_2 + \text{Mass of } Br_2 \]

From the given values:
\[ 31.7 \text{ grams of } HBr = 0.4 \text{ grams of } H_2 + \text{Mass of } Br_2 \]

Thus, the mass of Br₂ can be calculated as:
\[ \text{Mass of } Br_2 = 31.7 \text{ grams} - 0.4 \text{ grams} \]
\[ \text{Mass of } Br_2 = 31.3 \text{ grams} \]

Therefore, the mass of Br₂ formed is:

\[ \boxed{31.3} \text{ grams Br}_2 \]
Transcribed Image Text:### Decomposition of Hydrobromic Acid (HBr) The compound HBr (hydrobromic acid) can be decomposed to form hydrogen gas (H₂) and bromine gas (Br₂). This chemical reaction can be represented at the atomic level by the equation: \[ \mathbf{2HBr \rightarrow H_2 + Br_2} \] According to the law of conservation of mass, the mass of the reactants must equal the mass of the products. Given the scenario: - **Given Data:** - 31.7 grams of HBr decomposes. - 0.4 grams of H₂ is formed. - **Question:** - How many grams of Br₂ must simultaneously be formed? **Solution:** To determine the mass of Br₂ formed, consider the mass conservation principle: \[ \text{Mass of } HBr = \text{Mass of } H_2 + \text{Mass of } Br_2 \] From the given values: \[ 31.7 \text{ grams of } HBr = 0.4 \text{ grams of } H_2 + \text{Mass of } Br_2 \] Thus, the mass of Br₂ can be calculated as: \[ \text{Mass of } Br_2 = 31.7 \text{ grams} - 0.4 \text{ grams} \] \[ \text{Mass of } Br_2 = 31.3 \text{ grams} \] Therefore, the mass of Br₂ formed is: \[ \boxed{31.3} \text{ grams Br}_2 \]
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